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3 years ago

Change 3 to 5 in exercise 4

Mathematics

1 answer:

Nonamiya [84]3 years ago

5 0

So 5 4 3 I think yeah

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Walden's family is shopping for a reclining chair. The chair the family decided on has a retail price of $800 plus 5% sales tax

hoa [83]

I dont get what the letter mean what goes with each thing

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3 years ago

Lee Middle School orders 15 textbooks for every 12 students. The table shows how many textbooks the school orders for certain nu

Mariulka [41]

Answer: 90 textbooks

Step-by-step explanation:

everytime you multiply the number of students you multiply the books by the same number. to find how many times 72 was multiplied you divide it by 12.

72 ÷ 12 = 6

then multiply the original number of books (15) by 6.

15 * 6 = 90

so for every 72 students the school orders 90 textbooks

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3 years ago

Divide 270 in the ratio 3:2:1

Contact [7]

3 + 2 + 1 = 6

270 ÷ 6 = 45

45 × 3 = 135

45 × 2 = 90

45 × 1 = 45

3 : 2 : 1

135 : 90 : 45

6 0

3 years ago

(Anderson, 1.14) Assume that P(A) = 0.4 and P(B) = 0.7. Making no further assumptions on A and B, show that P(A ∩ B) satisfies 0

Goshia [24]

Answer with Step-by-step explanation:

We are given that

P(A)=0.4 and P(B)=0.7

We know that

$P(A)+P(B)+P(A\cap B)=P(A\cup B)$

We know that

Maximum value of $P(A\cup B)$ =1 and minimum value of $P(A\cup B)$ =0

$0\leq P(A\cup B )\leq 1$

$0\leq P(A)+P(B)-P(A\cap B)\leq 1$

$0\leq 0.4+0.7-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)\leq 1$

$0\leq 1.1-P(A\cap B)$

$P(A\cap B)\leq 1.1$

It is not possible that $P(A\cap B)$ is equal to 1.1

$1.1-P(A\cap B)\leq 1$

$-P(A\cap B)\leq 1-1.1=-0.1$

Multiply by (-1) on both sides

$P(A\cap B)\geq 0.1$

Again, $P(A\cup B)\geq P(B)$

$0.4+0.7-P(A\cap B)\geq 0.7$

$1.1-P(A\cap B)\geq 0.7$

$-P(A\cap B)\geq -1.1+0.7=-0.4$

Multiply by (-1) on both sides

$P(A\cap B)\leq 0.4$

Hence, $0.1\leq P(A\cap B)\leq 0.4$

3 0

3 years ago

Bobbie wants to make $2.00 using dollars ,half dollars , and quarters.how Many different ways can she make $2.00?

TEA [102]

70. Bobbie wants to make 2.00 dollars using dollars with the value of half dollars and quarters. Now, how many way he can do it? => half dollars = 0.5 => quarter dollars = 0.25 Possible ways: => 0.5 + 0.5 + 0.5 + 0.5 = 2 dollars (4 half dollars) => .25 + .25 + .25 +. 25 + .25 + .25 + .25 + .25 = 2 dollars (8 quarter dollars) => 0.5 + 0.5 + 0.25 + 0.25 + 0.25 + 0.25 = 2 dollars => 0.5 + 0.5 + 0.5 + 0.25 + 0.25 = 2 dollars => 0.5 + 0.25 + .25 + .25 + .25 + .25 + .25 = 2 dollars

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3 years ago