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Yanka [14]
3 years ago
7

-16b+32 can somebody help me factor this polynomial?

Mathematics
2 answers:
Readme [11.4K]3 years ago
7 0
Both terms are divisible by 16 or -16, depends on how you want the final factored product to turn out

factor out a 16
Scorpion4ik [409]3 years ago
7 0
-16+32
=-16(b-2)
Cheers,Irys
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Lucy and her mother made tacos they put 2 tacos on each of 7 plates selet the number sentences that show all the tacos Lucy and
slamgirl [31]
2 times 7 = 14
since each of the 7 guests received 2 tacos
3 0
4 years ago
Trevor paints 1/6 of the fence surrounding his farm each day. How many days will it take him to paint 3/4 of the fence?
VARVARA [1.3K]
To do this you have to divide 3/4 by 1/6.  To do this multiply 3/4 by the reciprocal of 1/6.  The reciprocal of 1/6 is 6/1.  So you have to multiply 3/4 and 6/1.  This will give you 18/4.  You now simplify it to 4 2/4, which can be simplified even more to 4 1/2.  It will take Trevor 4 1/2 days to paint 3/4 of the fence.  
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8 0
4 years ago
What are the roots of the quadric equation y=x^2-10x+125?
olganol [36]
5,100 um i’m not sure if that’s the answer you’re looking for
8 0
3 years ago
Three boxes contain 50 parts each. one part in each box is defective. one part is selected at random from each of the three boxe
Zanzabum
A. ) The probability of all 3 parts are non defective :-
48:3
B.) The probability that the part selected from box 1 is defective :-
1:1
The probability of the parts selected from box 2 and 3 are non defective :-
49:2
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------------------------------------------❌❌❌❌❌❌--------------------------------------------
6 0
3 years ago
I need math help. If youre solving a geometric sequence, the equation needed is An=A1Rn-1. If A1= 5 and R= -2. My question was "
CaHeK987 [17]

Answer:

Step-by-step explanation:

an = a1 * r^(n - 1)

a1 = first term = 5

r = -2

n = nth term of the sequence

so it starts with 5

second term is :

an = a1 * r^(n - 1)......for second term

a2 = 5 * -2^(2 - 1) =

a2 = 5 * -2^1

a2 = 5 * -2

a2 = -10

an = a1 * r^(n - 1)....looking for a3

a3 = 5 * -2^(3 - 1)

a3 = 5 * -2^2

a3 = 5 * 4

a3 = 20

an = a1 * r^(n - 1)....looking for a4

a4 = 5 * -2^(4 - 1)

a4 = 5 * -2^3

a4 = 5 * -8

a4 = - 40

an = a1 * r^(n - 1)...looking for a5

a5 = 5 * -2^(5 - 1)

a5 = 5 * -2^4

a5 = 5 * 16

a5 = 80

an = a1 * r^(n-1)...looking for a6

a6 = 5 * -2^(6 - 1)

a6 = 5 * -2^5

a6 = 5 * -32

a6 = -160

4 0
4 years ago
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