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IRISSAK [1]
3 years ago
6

How do you do 83 divided by 3 with long division

Mathematics
1 answer:
bulgar [2K]3 years ago
3 0

Answer:83÷3=27.6 or 27.667

Step-by-step explanation:

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What is the discriminante of 9x^2+10x
Leni [432]
The discriminant of y=ax^2+bx+c is b^2-4ac

given
9x^2+10x+0
a=9
b=10
c=0

discriminant=10^2-4(9)(0)=100-0=100

the discriminant is 100
6 0
3 years ago
4. x^2+13x=-42
Mrrafil [7]
x^2+13x=-42\ \ \ |+42\\\\x^2+13x+42=0\\\\x^2+6x+7x+42=0\\\\x(x+6)+7(x+6)=0\\\\(x+6)(x+7)=0\iff x+6=0\ \vee\ x+7=0\\\\x=-6\ \vee\ x=-7

Anaswer: <span>a. x = -6 or x = -7</span>

8 0
3 years ago
Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two
mafiozo [28]

Answer:

The difference of the original two-digit number and the number with reversed digits is 18.

Step-by-step explanation:

Since it's a two digit number, let x represent the tens digit and let y represent the units digit.

Thus, the original two digit number is;

10x + y.

The reverse two digit number is;

10y + x.

We are told that five times the sum of the digits of the two-digit number is 13 less than the original number.

Thus;

5(x + y) = (10x + y) - 13

Multiplying out the bracket gives;

5x + 5y = 10x + y - 13

Rearranging gives;

10x - 5x + y - 5y = 13

5x - 4y = 13 - - - - (3)

Also,we are told that, four times the sum of its two digits is 21 less than the reversed two-digit number. Thus;

4(x + y) = (10y + x) - 21 - - - (4)

Simplifying gives;

4x + 4y = 10y + x - 21

>> 10y - 4y - 4x + x = 21

>> 6y - 3x = 21 - - - (4)

Solving eq(3) and (4) simultaneously gives;

x = 5 and y = 3

Thus,

Original number = 53

Reversed number = 35

Difference between original and reversed number = 53 - 35 = 18

6 0
3 years ago
Simplify the expression.<br> - (m<br> m + 3n - 13)
natulia [17]

Answer:

=  -  {m}^{2}  - 3n + 13

Step-by-step explanation:

- (m \times m + 3n - 13)

m \times m =  {m}^{1}  \times m

{m}^{1}  \times  {m}^{1}  =  {m}^{1 + 1} =  {m}^{2}

- ( {m}^{2}  + 3n - 13)

=  -  {m}^{2}  - 3n + 13

7 0
3 years ago
Solve equation by factoring.
3241004551 [841]

Hi ;-)

x^2+6x-10=30 \ \ /-30\\\\x^2+6x-40=0\\\\a=1, \ b=6, \ c=-40\\\\\Delta=b^2-4ac=6^2-4\cdot1\cdot(-40)=36+160=196\\\\\sqrt{\Delta}=\sqrt{196}=14\\\\x_1=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-6-14}{2}=\boxed{-10}\\\\x_2=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-6+14}{2}=\boxed4

8 0
3 years ago
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