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Len [333]
3 years ago
11

A circle is inscribed in a square. Write and simplify an expression for the ratio of the area of the square to the area of the c

ircle. For a circle inscribed in a square, the diameter of the circle is equal to the side length of the square.
Mathematics
1 answer:
STALIN [3.7K]3 years ago
8 0
 Best Answer:<span>  </span><span>So first we need both areas, then we can relate them, and then divide the circle by the square: 

A(circle) = πr^2 
A(square) = L*W or (2r)*(2r) which is (2r)^2 

For the square, we know this is true because because the radius is half the diameter, so if we multiply the radius by 2, we get the length of one side of the square. We also know that the lengths of both sides of the square are the same by definition of a square. 

Ratio: (πr^2)/(4r^2) = π/4</span>
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15-3a =??<br> please help
scoundrel [369]

Answer:

a=5

Step-by-step explanation:

3 0
2 years ago
Kiran says that a solution to the equation x+4=20 must also be a solution to the equation 5(x+4)=100 Write a convincing explanat
Helen [10]

Answer:

x+4=20 is a solution to 5(x+4)=100.

Step-by-step explanation:

Following PEMDAS, divide 5 from both sides of the equation 5(x+4)=100, and you have x+4=20 remaining.

This means that both equations have the same solution.

8 0
3 years ago
Determine whether more or less than the percent budgeted was actually spent.
SSSSS [86.1K]

The amount spent as a percentage of the budget can be found from

... (actual amount)/(total budget) × 100%

... = (actual amount)/3600×100%

... = ((actual amount)/36)%

For housing, this is

... (820/36)% = 22.78% . . . . less than budget for housing

For transportation, this is

... (370/36)% = 10.28% . . . . more than budget for transportation

7 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
irga5000 [103]

Answer:

The rocket hits the ground at a time of 11.59 seconds.

Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

y = -16x^2 + 177x + 98

It hits the ground when y = 0, so we have to find x for which y = 0, which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

y = -16x^2 + 177x + 98

-16x^2 + 177x + 98 = 0

So

a = -16, b = 177, c = 98

\bigtriangleup = 177^{2} - 4(-16)(98) = 37601

x_{1} = \frac{-177 + \sqrt{37601}}{2*(-16)} = -0.53

x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

4 0
3 years ago
HELP Solve for x and y
BabaBlast [244]

Answer:

x = 96

y = 66

Step-by-step explanation:

The sum of interior angles of the given shape is 360:

x + y + 123 + 75 = 360

x + y + 198 = 360 subtract 198 from both sides

x + y = 162

The angle with the measure 114 and angle y are supplementary so their sum is 180

y + 114 = 180

y = 66 since x + y = 162 we can use this to find the value of x

x = 162 - 66

x = 96

5 0
2 years ago
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