Ask question

Ask question

All categories

3 years ago

7

Use the drop-down menus to complete the paragraph proof. we are given that xy is parallel to zw. if xz is a transversal that int

ercepts xy and zw, angle and angle are alternate interior angles. since xy is parallel to zw, we know that these angles are . we also know that angle xvy and angle zvw are angles, and thus congruent. we can conclude that △xyv ~ △zwv using the similarity theorem.

2 answers:

adoni [48]3 years ago

6 0

Solution:

x y ║ z w→→Given

Also, x z is a transversal, that intercepts x y and z w.

So, ∠ x z w=∠z x y→→Alternate interior angles as, x y ║ z w.

Also, v is point of intersection of x z and y w.

∠ x v y ≅ ∠ z v w→→[ Vertically opposite angles]

So,→→ Δ x y v ~ Δ z w v⇒⇒[Angle-Angle Similarity]

Vaselesa [24]3 years ago

6 0

Answer:

Step-by-step explanation:

Just did the assignment.

1. angle <u>YXV</u>

2. and angle <u>WZV</u>

3. angles are <u>congruent</u>

4. <u>vertical</u> angles

5. <u>AA</u>

You might be interested in

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

3 years ago

Solve algebraically 10+f=10

Sunny_sXe [5.5K]

10 + f = 10
-10 -10

f = 10 - 10

f = 0.

4 0

3 years ago

Ok what next helppp i need 2

pickupchik [31]

Answer:

3-2

Step-by-step explanation

8 0

2 years ago

Find the length of each missing side and each missing angle in the isosceles triangle below.

Zarrin [17]

Answer:

x = 45

y = 45

z = 11.1

Step-by-step explanation:

Remark

The triangle is a right triangle. That means that it has 1 right angle.

It is also isosceles which means that the two legs that are not the hypotenuse are equal.

Result: z and 11.1 are equal z = 11.1

More remark

If the triangle is isosceles, that means that the angles that are not right angles must also be equal.

90 + x + y = 180

but x = y

90 + 2x = 180 Subtract 90

2x = 180 - 90 Divide by 2

2x/2 = 90/2

x = 45

3 0

2 years ago

A $450 TV is discounted 10%, and then another 10% a week later. Explain why taking 20% off the original price will not help you

ExtremeBDS [4]

Answer:

Because the price did not stay the same when they discounted it by 10% percent before.

Step-by-step explanation:

10% percent of 450 is 45 so Subtracting that from 450 would give you,405.

They deducted another 10% percent a week later 10 percent of 405 would be 40.5 so you would subtract that from 405 which would make it 364.5

If you took 20% off originally then 20% of 450 is 90 so subtracting that would make 450 into 360 which is different from 364.5

4 0

3 years ago