Find the vertex of the parabola whose equation is y = x 2 + 8x + 12.
1 answer:
Answer:
(-4, -4)
Step-by-step explanation:
You have to put this in vertex form by completing the square in order to determine the vertex. Begin by setting the quadratic equal to 0 then moving the 12 over by subtraction:
The rules are to take half the linear term, square it, and add it to both sides. Our linear term is 8. Half of 8 is 4, and 4 squared is 16. So we add 16 to both sides:
During this process we have created a perfect square biomial on the left. We will state that, along with simplifying on the right:
Now we will move the 4 back over and set it back to equal y:
And from this you can see that the coordinates of the vertex are (-4, -4)
You might be interested in
Answer:
-2x
Step-by-step explanation:
Graph
y > −2x + 3
Use the slope-intercept form to find the slope and y-intercept.
The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
y = mx + b
Find the values of m and b using the form y = mx + b. m = −2
b = 3
The slope of the line is the value of m, and the y-intercept is the value of b.
Slope: −2
intercept: (0, 3)
Graph a dashed line, then shade the area above the boundary line since y is greater than
−2x + 3.
y > −2x + 3
