Define a substitution method to solve the followingsysten of equation of y=2x-3, x+y=1

1 answer:

Ivan3 years ago

7 0

I will solve you system by substitution

y = 2x - 3 ; x + y = 1

→Step 1: Solve y = 2x - 3 for y

→Step 2: Substitute 2x - 3 for y in x + y = 1:

x + y = 1

x + 2x- 3 = 1

3x - 3 = 1 (Simplify both sides of the equation)

3x - 3 + 3 = 1 + 3 (Add 3 both sides)

3x = 4

3x ÷ 3 = 4 ÷ 3 (Divide each side by 3)

x = 4/3

→Step 3: Substitute 4/3 for x in y = 2x - 3:

y = 2x - 3

y = 2 (4/3) -3

y = -1/3 (Simplify both sides of the equation)

Answer:

x = 4/3 and y = -1/3

∫Hope that helps∫

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$\quad\rule{300pt}{1pt}$

<h3>Solution:</h3>

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