Question

The first term of a geometric sequence is -2 and the common ratio is 3 what is the 12th term of the sequence

Answer 1

The n-th term of a geometric sequence with initial value a and common ratio r is given by $a_n=a_1r^{n-1}$.

We have $a_1=-2$ and $r=3$ and $n=12$

Substitute:

$a_{12}=-2\cdot3^{12-1}=-2\cdot3^{11}=-2\cdot177147=-354294$