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andrew11 [14]
3 years ago
9

Sue travels by bus or walks when she visits the shops. The probability that she catches the bus to the shops is 0.4. The probabi

lity she catches the bus from the shops is 0.7. Show the probability that Sue walks at one way is 0.72
Mathematics
1 answer:
Ksenya-84 [330]3 years ago
3 0

Answer:

Proved,

P(A∪B)=0.72

Step-by-step explanation:

Sue travels by bus or walks when she visits the shops.

Probability( catch the bus to the shop ), P(A) = 0.4

Probability( catch the bus from the shop ), P(B) = 0.7

Both A and B are independent events.

Therefore,

P(A∩B) = 0.4×0.7

           = 0.28

Probability Sue walks one way = 1 - P(A∩B)

                                                   = 1 - 0.28

                                                   = 0.72

Hence, the probability that Sue walks at one way is 0.72

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