All categories

3 years ago

Can you please help me with this worksheet (this is due tomorrow)

Mathematics

1 answer:

Flauer [41]3 years ago

8 0

Jennifer
1. 6
2.26
3.42
4.82

erika
1.7 (erika wrong)
2.15 (right)
3.23 (right)
4.43 (right)

6a. 6 is the right one
2(6+2)-7=9

You might be interested in

alex container of cranberry juice holds 200 milliters. harrys container holds 7/8 as much juice. how many milliliters of cranber

blondinia [14]

175mm??? Im not entirely sure.

6 0

3 years ago

Y < 3 includes three as a possible solution

irakobra [83]

False...it does not include 3....it includes only numbers less then 3.

For it to include 3, u would need an equal sign in there..
Y < = 3...(thats less then or equal)...this would include 3

6 0

3 years ago

Which of the following is the measure of an acute angle?

gladu [14]

There is no image, but I can help you by telling you what an acute angle is:

An acute angle is any angle that has a measure LESS then 90 degrees

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0

3 years ago

Read 2 more answers

Bacgvcfbbnnnbvvbbbgggggggggggggggg

REY [17]

Answer:

2) x=u/2+1

4) a=g/c

6) x=g-c

8) =g/c

Step-by-step explanation:

hope this is helpful

5 0

3 years ago

There are 40 students,

egoroff_w [7]

answer

$\frac{621}{2000}$ ≈ 0.31 = 31 %

set up equation

the probability of someone from the first group having brown eyes is $\frac{students-with-brown-eyes-in-first-group}{total-students-in-first-group }$

the probability of someone from the second group having brown eyes is $\frac{students-with-brown-eyes-in-second-group}{total-students-in-second-group }$

so the probability of both students having brown eyes is $\frac{students-with-brown-eyes-in-first-group}{total-students-in-first-group }$ * $\frac{students-with-brown-eyes-in-second-group}{total-students-in-second-group }$

values

students with brown eyes in first group = 27

total students in first group = 40

students with brown eyes in second group = 23

total students in second group = 50

plug in values and solve

$\frac{students-with-brown-eyes-in-first-group}{total-students-in-first-group }$ * $\frac{students-with-brown-eyes-in-second-group}{total-students-in-second-group }$

= $\frac{27}{40} *\frac{23}{50}$

= $\frac{27 * 23}{40 * 50}$

= $\frac{621}{2000}$

≈ 0.31

= 31 %

8 0

3 years ago