The standard conversion toolbox:
x=rcos(θ)
y=rsin(θ)
Here r=7csc(θ)
so
x=7csc(θ)*cos(θ)=7cos(θ)/sin(θ)=7cot(<span>θ)
y=7csc(</span>θ)*sin(θ)=7sin(θ)/sin(<span>θ) = 7
therefore the rectangular coordinates are (7cot(</span><span>θ), 7)</span>
The answer is <span>Q=(M−2P)/3
</span>
<span>M = 2P + 3Q
Subtract 2P from both sides:
M - 2P = 2P + 3Q - 2P
M - 2P = 3Q
Divide both sides by 3:
(M - 2P)/3 = 3Q/3
(M - 2P)/3 = Q</span>
<span>Twice the sum of a number and 3 = 2(n + 3)
</span><span>three times the difference of the number and 3 = 3(n - 3)
so
</span><span>Twice the sum of a number and 3 is equal to three times the difference of the number and 3:
</span>2(n + 3) = 3(n - 3)
2n + 6 = 3n - 9
n = 15
answer
2(n + 3) = 3(n - 3)
n = 15
Answer:
Step-by-step explanation:
Given: sum of the smallest integer and four times the largest integer out of three consecutive odd integers is 61
To list: numbers from least to greatest
Solution:
Let the three consecutive odd integers be 
.
According to question,
So, the integers are 
Numbers from least to the greatest:
can you give more detail?
