This is a modulus inequality.
First part: when (6x + 2) is positive
6x + 2 < 10
6x < 10 - 2
6x < 8
x < 8/6
x < 4/3
Second part: when (6x + 2) is negative.
-(6x + 2) < 10 Divide both sides of inequality by -1 and change the sign.
(6x + 2) > -10
6x + 2 > -10
6x > -10 - 2
6x > -12 Divide both sides by 6.
x > -12/6
x > -2.
Combined solution: x < 4/3 and x > -2
-2 < x < 4/3.
Graph is a line on the number line between -2 and 4/3.
-2 and 4/3 are excluded from solution.
X = first integer, y = second integer (right after x)
since y is right after x, we can say
y = x+1
If the product of the two integers (x and y) is 42, then
x*y = 42
x*( y ) = 42
x*( x+1 ) = 42 ... y is replaced with x+1
x*x + x*1 = 42
x^2 + x = 42
x^2 + x - 42 = 0
(x + 7)(x - 6) = 0 ... factor
x + 7 = 0 or x - 6 = 0
x = -7 or x = 6
The result must be positive as the problem states it, so we toss out x = -7
The only answer is x = 6
If x = 6, then
y = x+1
y = 6+1
y = 7
The two consecutive numbers are 6 and 7
The final answer is 6
Sure enough, 6*7 = 42 checks out
All I can say is 1 and 2 are correct.
Answer:
A (2,-2.5)
Step-by-step explanation:
Is 2 units right and 2.5 units down, right where point C is.
Step-by-step explanation:
g(x) = 3x - 2
g(-4) = 3(-4) - 2
= -12 -2
= -14
