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Svetradugi [14.3K]
3 years ago
15

What is the answer to 70+92

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
8 0
162 is the answer. Hope this helps.
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SOMEONE PLEASE EXPLAIN!!
just olya [345]

To find if something is a parallelogram, they 1 set of line segments need to have the the slope. In this equation, Slope equals x1 + x2 divided by y1 + y2 (Or the other way around, x2 + x1 divided by y2 + y1)

m =  \frac{( - 3 + 1)}{ ( 1 + 3)}  =  \frac{ - 2}{4}  =  -  \frac{1}{2}

For your other point, it could be (-4,5)

If this is confusing, please tell me! I'll try to better explain. It also helps to draw out a graph so you can plot the points.

6 0
3 years ago
Which is a solution to the equation |10-5y| = 20?
ioda

Answer:

{-2, 6}

Step-by-step explanation:

10-5y=20

-5y=10

y=-2

10-5y=-20

-5y=-30

y=6

6 0
3 years ago
Mary goes walking every day. She walks 14 ft. every 4 seconds. Which equation models the relationship between the time Mary walk
lilavasa [31]

Answer:

y=3.5x

Step-by-step explanation:

to find the the feet mary walks per second, divide 14 by 4

14/4=3.5 feet/second

the total distance mary walks can be represented by multiplying the number of feet she walks per second by the number of seconds she walks

y= 3.5x

in this model, x is seconds

6 0
2 years ago
2 1/2 divide by 1/4 and how to write a real problem for it
den301095 [7]
2 1/2 = (2*2+1)/2 = 5/2
5/2 : 1/4 = 5/2 * 4/1 = 20/2 = 10
5 0
4 years ago
Find the following Euler Totients using Euler’s Theorem, as explained on p.409 of the text (10 points each): a.ϕ(13) b.ϕ(81) c.ϕ
ad-work [718]

(a) \varphi(13)=12 since 13 is prime.

(b) 81=3^4, and there are 81/3 = 27 multiples of 3 between 1 and 81, which leaves 81 - 27 = 54 numbers between 1 and 81 that are coprime to 81, so \varphi(81)=54.

(c) 100=2^2\cdot5^2; there are 50 multiples of 2, and 20 multiples of 5, between 1 and 100; 10 of these are counted twice (the multiples of 2*5=10), so a total of 50 + 20 - 10 = 60 distinct numbers not coprime to 100, leaving us with \varphi(100)=100-60=40.

(d) 102=2\cdot3\cdot17; there are 51 multiples of 2, 34 multiples of 3, and 6 multiples of 17, between 1 and 102. Among these, we double-count 17 multiples of 2*3=6, 3 multiples of 2*17=34, and 2 multiples of 3*17=51; we also triple-count 1 number, 2*3*17=102. There are then 51 + 34 + 6 - (17 + 3 + 2) + 1 = 70 numbers between 1 and 102 that are not coprime to 102, and so \varphi(102)=102-70=32.

4 0
4 years ago
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