Question

In a certain Algebra 2 class of 21 students, 6 of them play basketball and 14 of them play baseball. There are 5 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

Answer 1

Answer:

Step-by-step explanation:

5 of them play neither sport.

We can subtract 5 from 21 to get the kids that play a sport.

16-(14+6), is -4.

so 4 is the number of kids that play both sports.

so the probability is 4/21.

Answer 2

Answer:4

Step-by-step explanation:

To find this

The universal set is 21

To find number of the that played both basket ball and baseball

6-x+14-x+5+x=21

Collect like terms

25-x=21

x=4

Therefore the number of students that play both basket ball and baseball is 4