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aleksklad [387]
3 years ago
10

Check my answer :D

Mathematics
2 answers:
Dimas [21]3 years ago
7 0
Hello,
your answer should be true if you put parenthesis!

=1/2[log base 9(57)-log base9 (74)]
=1/2 log base 9 (57)-1/2 log base 9(74)




LuckyWell [14K]3 years ago
4 0

Answer:

Yes the answer is correct explained in step-by-step explaination.

Step-by-step explanation:

Given the logarithmic expression

log(base b)square root 57/74

\log_{b}\frac{\sqrt57}{74}

Now we know that \log \frac{m}{n} =\log m-\log n\\\log x^{\frac{1}{2} } =\frac{1}{2}\log x

Hence, log _{b}\sqrt57=\frac{1}{2}log _{b}57

∴log_{b}\frac{\sqrt57 }{74}=log_{b}{\sqrt57 }-log_{b}{54}  

\frac{1}{2}log_{b}57-log_{b}54

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What is the solution to the system? 1. x-y + 2 z = -7<br> 2. y + z =1<br> 3. x-2 y - 3 z = 0
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You'd find this problem easier to understand and do if you'd please list the defining equations vertically and line up variables:

1. x - 1y + 2 z = -7

2. y + 1z = 1

3. x - 2 y - 3 z = 0 Now eliminate the line numbers:

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Let's use the elimination method to eliminate variable z: Seeing that z = 1 - y, we transform the first equation into 1x - 1y + 2(1-y) = -7

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Having eliminated the variable z, we now focus on eliminating x. Mult. the 1st equation by -1, obtaining -1x - 1y = -3. Add this result to 1x - 3y = -9:

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Borrowing Equation 3, from above, we get x - 2 y - 3 z = 0, and into this equation we substitute x = 0 and y = 3: 0 -2(3) - 3z = 0.

Thus, -3z = 6, and z = -2.

The solution set is (0, 3, -2). You should check this by substitution.

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