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aleksklad [387]
3 years ago
10

Check my answer :D

Mathematics
2 answers:
Dimas [21]3 years ago
7 0
Hello,
your answer should be true if you put parenthesis!

=1/2[log base 9(57)-log base9 (74)]
=1/2 log base 9 (57)-1/2 log base 9(74)




LuckyWell [14K]3 years ago
4 0

Answer:

Yes the answer is correct explained in step-by-step explaination.

Step-by-step explanation:

Given the logarithmic expression

log(base b)square root 57/74

\log_{b}\frac{\sqrt57}{74}

Now we know that \log \frac{m}{n} =\log m-\log n\\\log x^{\frac{1}{2} } =\frac{1}{2}\log x

Hence, log _{b}\sqrt57=\frac{1}{2}log _{b}57

∴log_{b}\frac{\sqrt57 }{74}=log_{b}{\sqrt57 }-log_{b}{54}  

\frac{1}{2}log_{b}57-log_{b}54

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Rewrite each expression in terms of sine and cosine only.
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Answer:

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Step-by-step explanation:

1. SecθCotθ

Recall

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Recall

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Thus,

Cos²θ = Cos²θ + Sin²θ – Sin²θ

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