Answer:
The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.
Step-by-step explanation:
A gallon equals 0.134 cubic feet. First, we determine the amount of water (
), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:
(1)
Where:
- Volume rate, measured in feet per minute.
- Time, measured in minutes.
If we know that
and
, then the amount of water is:
![Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)](https://tex.z-dn.net/?f=Q%20%3D%20%5Cleft%282000%5C%2C%5Cfrac%7Bgal%7D%7Bmin%7D%20%5Cright%29%5Ccdot%20%28120%5C%2Cmin%29%20%5Ccdot%20%5Cleft%280.134%5C%2C%5Cfrac%7Bft%5E%7B3%7D%7D%7Bgal%7D%20%5Cright%29)
![Q = 32160\,ft^{3}](https://tex.z-dn.net/?f=Q%20%3D%2032160%5C%2Cft%5E%7B3%7D)
And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:
(2)
Where:
- Diameter, measured in feet.
- Height, measured in feet.
If we know that
and
, then the minimum diameter is:
![D^{2} = \frac{4\cdot Q}{\pi\cdot h}](https://tex.z-dn.net/?f=D%5E%7B2%7D%20%3D%20%5Cfrac%7B4%5Ccdot%20Q%7D%7B%5Cpi%5Ccdot%20h%7D)
![D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }](https://tex.z-dn.net/?f=D%20%3D%202%5Ccdot%20%5Csqrt%7B%5Cfrac%7BQ%7D%7B%5Cpi%5Ccdot%20h%7D%20%7D)
![D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }](https://tex.z-dn.net/?f=D%20%3D%202%5Ccdot%20%5Csqrt%7B%5Cfrac%7B32160%5C%2Cft%5E%7B3%7D%7D%7B%5Cpi%5Ccdot%20%2812%5C%2Cft%29%7D%20%7D)
![D \approx 58.415\,ft](https://tex.z-dn.net/?f=D%20%5Capprox%2058.415%5C%2Cft)
The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.