First put these in order from least to greatest.
1,2,2,4,8,9,9 is the correct order
Range is when we subtract the greatest value of our data set from the smallest so in our case it would be 9-1 which leaves us with our answer that 8 is your range.
Answer:
it is 5x;b=-1x;c=5
Step-by-step explanation:
Answer:
x^3 - 3x^2 - 3x + 9 + (-36/(x+3))
OR
x^3 - 3x^2 - 3x + 9 - (36/(x+3))
Step-by-step explanation:
First set the divisor equal to 0:
x + 3 = 0
Subtract 3 from both sides
x = -3
This is what you'll divide the dividend by in synthetic division.
Take the coefficents of each term in the dividend. Do not forget the 0 placeholders:
x^4 + 0x^3 - 12x^2 + 0x -9
Coefficents: 1. 0. -12. 0 -9.
Please see the image for the next steps.
The remainder is -36. Put the remainder over the divisor and add it to the polynomial (shown in image)
-36/(x+3)
Given that the triangle is dilated by factor 3, the image will be found as follows;
The object is at:
A(-7,-3), B(-3,-2), C(-4,-5)
when the image was enlarged the new coordinates will be:
A'=3(-7,-3)=(-21,-9)
B'=3(-3,-2)=(-9,-6)
C'=3(-4,-5)=(-12,-15)
since the image is centered at the point (-7,-6), the final point will be at:
A"=[(-21+-7),(-9+-6)=(-28,-15)
B''=[(-9+-7),(-6+-6)]=(-16,-12)
C''=[(-12+-7),(-15+-6)]=(-19,-17)
thus the coordinates of the final image are:
A''(-28,-15),B''(-16,-12),C''(-19,-17)
Answer:
<h3><em>
(12, -6)</em></h3>
Step-by-step explanation:
The formula for calculating the midpoint of two coordinates is expressed as shown;
M(X, Y) = [(x1+x2)/2, (y1+y2)/2]
Given the midpoint of ST to be ((6, -2) and one endpoint T is (0,2), according to expression above;
X = (x1+x2)/2
Y = (y1+y2)/2
From the coordinates, X = 6, Y = -2, x1 = 0 and y1 = 2, to get x2 and y2;
X = (x1+x2)/2
6 = (0+x2)/2
cross multiply
12 = 0+x2
x2 = 12-0
x2 = 12
For 2;
Y = (y1+y2)/2
-2 = (2+y2)/2
cross multiply
-4 = 2+y2
y2 = -4-2
y2 = -6
<em>Hence the other endpoint S(x2, y2) is (12, -6)</em>
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