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Natasha2012 [34]
3 years ago
14

Can someone please help with these please!!

Mathematics
2 answers:
Aleksandr-060686 [28]3 years ago
6 0
27/57 I hope I helped you
ryzh [129]3 years ago
5 0

Answer:

27.57

is the Mean

20 is the mode (most repetative)

26 is the median (the number in the middle when in order)

Step-by-step explanation:

SO they look better by using their Mean Score 27.57 Points

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Brent is making a playlist for an upcoming trip. The average length of a song is 3.53 minutes If the flight is about 120 minutes
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Answer:

34 songs

Step-by-step explanation:

120min/3.53 = 33.99

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The frequency of vibrations of a vibrating violin string isgiven by
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Answer:a. [tex] $f\propto  L$ [\tex]

b. [tex] f \propto \sqrt{T} [\tex]

c. [tex] f \propto \frac{1}{\sqrt{P}} [\tex]

I. Decrease in length increases leads to increase in pitch.

II. Increase in tension leads to increase in pitch.

III. Increase in linear density reduces the pitch

Step-by-step explanation: I. Since the frequency is inversely proportional to the length increase in length leads to decrease in frequency likewise decrease in length leads to increase in frequency.

II. Since the frequency is directly proportional to the square root of the tension increase in tension leads to increase in frequency likewise decrease in tension leads to decrease in frequency.

III.since the frequency is inversely proportional to the square root of the linear density so increase in linear density leads to decrease in frequency and likewise decrease in linear density leads to increase in frequency.

7 0
3 years ago
Solving Rational equations. LCD method. Show work. Image attached.
posledela

(k-2)(k-6)=k^2-2k-6k+12=k^2-8k+12

So in order to get all the fractions to have a common denominator, we need to multiply \dfrac k{k-2} by \dfrac{k-6}{k-6}, and \dfrac1{k-6} by \dfrac{k-2}{k-2}:

\dfrac k{k-2}\cdot\dfrac{k-6}{k-6}=\dfrac{k(k-6)}{(k-2)(k-6)}=\dfrac{k^2-6k}{k^2-8k+12}

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Now,

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We can factorize the right side:

0=(k-6)(k+1)

which tells us that k=6 and k=-1 are solutions.

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4 years ago
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