Prepare for trouble...

Mathematics

2 answers:

liubo4ka [24]2 years ago

4 0

Answer:

what do you mean

Step-by-step explanation:

alex41 [277]2 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

One end point of a line segment is ( -3, -6 ) The length of the line segment is 7 units find four points that could serve as the

Rina8888 [55]

Answer:

(-3, 1), (-3, -13), (4, -6), (-10, -6)

Step-by-step explanation:

You can think of point (-3, -6) as the center of a circle of radius 7. Then all points on the circle are 7 units from point (-3, -6). There are 4 points 7 units away from point (-6, -3) whose coordinates are easy to find. Think of a vertical line and a horizontal line that go through point (-3, -6). Up and sown from point (-3, -6) are points (-3, 1) and (-3, -13). To the right and left of point (-3, -6) are points (4, -6) and (-10, -6).

8 0

2 years ago

Read 2 more answers

Find the surface area of the

sladkih [1.3K]

Answer:

216

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x

Savatey [412]

The polynomial remainder theorem states that the remainder upon dividing a polynomial $p(x)$ by $x-c$ is the same as the value of $p(c)$ , so to find $p(-10)$ you need to find the remainder upon dividing

$\dfrac{2x^3+14x^2-58x}{x+10}$

You have

..... | 2 ... 14 ... -58
-10 | ... -20 ... 60
--------------------------
..... | 2 ... -6 .... 2

So the quotient and remainder upon dividing is

$\dfrac{2x^3+14x^2-58x}{x+10}=2x-6+\dfrac2{x+10}$

with a remainder of 2, which means $p(-10)=2$ .