Round 3.99408317124 to the nearest tenth.

I really need help pls helpme

DaniilM [7]

Answer:

-35

Step-by-step explanation:

Trust

7 0

4 years ago

HELP FAST I'LL MARK YOU BRAINLIEST

brilliants [131]

Answer:

4

Step-by-step explanation:

In a rhombus, the diagonals are congruent. It is not always true. If the diagonals become congruent then It becomes square. Hope this helps!

4 0

3 years ago

Read 2 more answers

miguel is posting photos on a school website. He has 48 photos, and he is allowed to use 12 pages. He wants to put the same numb

Vlad1618 [11]

Answer:

4 pages

Step-by-step explanation:

48 divided by 12 = 4

8 0

2 years ago

Dave walked to his friend's house at a rate of 4 mph and returned back biking at a rate of 10 mph. If it took him 18 minutes lon

katrin [286]

Answer:

4 miles

Step-by-step explanation:

<u>Walking:</u>

Distance = d miles

Rate = 4 mph

Time = t hours

$d=4\cdot t$

<u>Biking:</u>

Distance = d miles

Rate = 10 mph

Time $=t-\dfrac{18}{60}=t-0.3$ hours (convert minutes to hours)

$d=10\cdot (t-0.3)$

Hence,

$4t=10(t-0.3)\\ \\4t=10t-3\\ \\4t-10t=-3\\ \\-6t =-3\\ \\6t=3\\ \\t=\dfrac{3}{6}=\dfrac{1}{2}=0.5\ hour$

Therefore, the distance to friend's house is

$d=4\cdot 0.5=2\ miles$

and the total distance of the round trip is

$2+2=4\ miles$

6 0

3 years ago

Suppose M is the midpoint of Segment AB, P is the midpoint of Segment AM, and Q is the midpoint of segment PM.

DerKrebs [107]

The coordinates of M, P and Q in terms of a and b are $M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$ , $P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$ and $Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$ , respectively.

In this question we are going to use definitions of vectors and product of a vector by a scalar. Based on the information given on statement, we have the following vectorial formulas:

Location of M

$\overrightarrow{AM} = \frac{1}{2}\cdot \overrightarrow{AB}$

$\vec M - \vec A = \frac{1}{2}\cdot \vec B - \frac{1}{2}\cdot \vec A$

$\vec M = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec B$

$M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$

Location of P

$\overrightarrow{AP} = \frac{1}{2}\cdot \overrightarrow{AM}$

$\vec P - \vec A = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec A$

$\vec P = \frac{1}{2}\cdot \vec A +\frac{1}{2}\cdot \vec M$

$\vec P = \frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B$

$P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$

Location of Q

$\overrightarrow{QM} = \frac{1}{2}\cdot \overrightarrow{PM}$

$\vec M - \vec Q = \frac{1}{2}\cdot \vec M - \frac{1}{2}\cdot \vec P$

$\vec Q = \frac{1}{2}\cdot \vec P - \frac{1}{2}\cdot \vec M$

$\vec Q = \frac{1}{2}\cdot \left(\frac{3}{4}\cdot \vec A + \frac{1}{4}\cdot \vec B\right) -\frac{1}{2}\cdot \left(\frac{1}{2}\cdot \vec A + \frac{1}{2}\cdot \vec B\right)$

$\vec Q = \frac{1}{8}\cdot \vec A -\frac{1}{8}\cdot \vec B$

$Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$

The coordinates of M, P and Q in terms of a and b are $M = \frac{1}{2}\cdot a + \frac{1}{2}\cdot b$ , $P = \frac{3}{4}\cdot a + \frac{1}{4}\cdot b$ and $Q = \frac{1}{8}\cdot a - \frac{1}{8}\cdot b$ , respectively.

We kindly invite to check this question on midpoints: brainly.com/question/4747771

4 0

2 years ago