4 years ago

Find the area of the composite shape shown.

Mathematics

1 answer:

taurus [48]4 years ago

5 0

Answer:

Step-by-step explanation:

if i am right you should take 15 and 6 and 10 times hope this you =)

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What is the complete question?

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3 years ago

Andre was trying to write 7^4/7^-3 with a single exponent and write 7^4/7^-3= 7^4-3=7^1 Exploit to Andre what his mistake was an

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$\frac{7^4}{7^{-3}}=7^7$

Here, we want to get what Andre's mistake was and correct it

To answer this, we are supposed to use the division law of indices

We have this as;

$\frac{a^x}{a^y\text{ }}=a^{x-y}$

Now, in the case of this question, x is 4 and y is -3

So, we have the expression as;

$7^{4-(-3)}=7^{4+3}=7^7$

His mistake is thus adding the exponents instead of subtracting

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1 year ago

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3 years ago

the intensity, I, of light varies inversely as the square of the distance, D2 , from the light source. If I is 150 units when D

podryga [215]

$\bf \textit{\underline{x} varies inversely with }\underline{z^5} ~\hspace{5.5em} \stackrel{\textit{constant of variation}}{x=\cfrac{\stackrel{\downarrow }{k}}{z^5}~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{\underline{I} varies inversely with }\underline{D^2}}{I = \cfrac{k}{D^2}} \qquad \qquad \textit{we also know that } \begin{cases} I=150\\ D=6 \end{cases}$

$\bf 150=\cfrac{k}{6^2}\implies 150=\cfrac{k}{36}\implies 5400=k~\hfill \boxed{I=\cfrac{5400}{D^2}} \\\\\\ \textit{when I = 24, what is \underline{D}?}\qquad \qquad 24=\cfrac{5400}{D^2}\implies D^2=\cfrac{5400}{24} \\\\\\ D^2=225\implies D=\sqrt{225}\implies D=15$

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4 years ago

HELP REALLY QUICK PLEASE

chubhunter [2.5K]

Answer:

The answer is 140

The yellow part which is shaded is 14x10 which equals 140

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3 years ago

Find the area of the composite shape shown.​

Find the area of the composite shape shown.