Question

Andre was trying to write 7^4/7^-3 with a single exponent and write 7^4/7^-3= 7^4-3=7^1 Exploit to Andre what his mistake was and what the answer should be...PLEASE THE ANSWER IS URGENT!!

Answer 1

$\frac{7^4}{7^{-3}}=7^7$

Here, we want to get what Andre's mistake was and correct it

To answer this, we are supposed to use the division law of indices

We have this as;

$\frac{a^x}{a^y\text{ }}=a^{x-y}$

Now, in the case of this question, x is 4 and y is -3

So, we have the expression as;

$7^{4-(-3)}=7^{4+3}=7^7$

His mistake is thus adding the exponents instead of subtracting