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Aneli [31]
3 years ago
11

Twelve eggs cost $2.09.How much would 18 eggs cost?

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
8 0
12 egg=2.09
then your adding 6 more eggs to get 18 eggs and 6 is half of 12
so you would be adding half the price
2.09/2=1.05
so then add 2.09+1.05=3.14
So 18 eggs would be $3.14

Hope this helps!! :D
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Determine what fraction is the correct label for
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1.5/3
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5 0
2 years ago
The average weight of 10 boys is 77.0 pounds. If the
n200080 [17]

Answer:

68 pounds.

Step-by-step explanation:

Find the total weight when there are 10 boys and when there are 9 boys then calculate the difference.

I'll let x = total weight.

\frac{x}{10}=77\\(10)\frac{x}{10}=77(10)\\x=770\\\\ \frac{x}{9}=78\\(9)\frac{x}{9}=78(9)\\x=702\\\\ 770-702=68

Therefore, the youngest boy weighs 68 pounds.

4 0
3 years ago
I will legit give you all the internet points if you can give me a legit answer.
alexgriva [62]

Answer:

O Option A/1

Step-by-step explanation:

Take LCM.

4x+3(2x² - 8x) + 24x / x(2x² - 8x)

= 8x³ + 6x² - 32x² - 24x + 24x / 2x³ - 8x²

= 8x³ - 26x² / 2x³ - 8x²

= 4x - 13 / x - 4

7 0
2 years ago
Read 2 more answers
Suppose that A A is a set containing 13 13 elements. Find the number of different subsets of A.
aivan3 [116]

Answer:

number of subsets of a set with 13 elements are: 2^{13}

Step-by-step explanation:

In order to solve this intuitively, we can start by a set with lesser elements. This will reveal a pattern that will be used to solve for the subsets of the 13 element set.

If we start with a set B. which contains only 3 elements.

B = \{1,2,3\}

how many subsets of B are there? well we can count them. [the set containing {1,2} and {2,1} are the same, arrangement doesn't matter]

B_{0} = \{\}\\B_{1a}=\{1\}\\B_{1b}=\{2\}\\B_{1c}=\{3\}\\B_{2a}=\{1,2\}\\B_{2b}=\{2,3\}\\B_{2c}=\{3,1\}\\B_{3a}=\{1,2,3\}\\

there are a total of 9 subsets here.

Similarly, if you try a with a subset with only two elements you'll find that it has a total of 4 subsets.

We can see that combinatorics is at play here.

for the set B. the number of subsets can be written as:

\text{\# of subsets of B} = ^3C_0+^3C_1+^3C_2+^3C_3\\\text{\# of subsets of B} = 1+3+3+1\\\\text{\# of subsets of B} = 8

if we try with a 2-element set:

\text{\# of subsets} = ^2C_0+^2C_1+^2C_2\\\text{\# of subsets} = 1+2+1\\\ \text{\# of subsets} = 4

We can use the same technique to find the number of subsets of the 13 element set.

But if you recognize a pattern here that this sets of combinations are actually part of the pascal triangle, the sum of each row of the triangle is 2^{the row's number}. hence.

\text{\# of subsets of B} = 2^3\\\ \text{\# of subsets of B} = 8

So finally, the subsets of a 13-element set A will be

\text{\# of subsets of A} = ^{13}C_0+^{13}C_1+^{13}C_2+^{13}C_3\cdots+^{13}C_{12}+^{13}C_{13}\\OR\\\text{\# of subsets of A} = 2^{13}\\\text{\# of subsets of A} = 8192

6 0
3 years ago
Help help help help math math
Sav [38]
You cross multiple. Remember 5 = 5/1

So x/2 = 5/1

Cross multiple x is linked with 1 and 2 is lined with 5.

So x(1) = 5(2)

X = 10
4 0
2 years ago
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