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3 years ago

Help pleasesolve for X

Mathematics

2 answers:

cupoosta [38]3 years ago

4 0

What the person said above! I had the same question

Mila [183]3 years ago

3 0

Answer:

Step-by-step explanation:

those angles are congruent because they are vertical angles

6x+4 = 58 ; subtract 4 from both sides

6x = 58-4 ; combine like terms

6x = 54; divide both sides by 6

x= 9

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4 divided by 12 is 1/3.
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2 years ago

Ivy invests $1000 at a simple interest rate of 7%. How much interest will Ivy earn in 3 years * $2100 $70 $210 I don't know

ololo11 [35]

Answer:$210

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2 years ago

Read 2 more answers

A kite is flying at the end of a 20-meter string. If the string makes an angle of 55° with the ground, how many meters above the

Mama L [17]

Answer:

Step-by-step explanation:

8 0

3 years ago

A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m

photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

Mass of the car, v1 = 1500 kg

initial speed of car = 35 miles/h

$=\dfrac{35\times 1609.34}{3600}\ m/s$

= 15.64 m/s

Initial kinetic energy of the car is given by,

$k_1\ =\ \dfrac{1}{2}.m.v_1^2$

$=\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule$

= 183606.46 J

Final velocity of car v2 = 70 miles/hour

$=\dfrac{70\times 1609.34}{3600}$

= 31.29 m/s

So, final kinetic energy of car is given by

$k_2\ =\ \dfrac{1}{2}.m.v_2^2$

$=\ \dfrac{1}{2}\times 1500\times (31.29)^2$

= 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

$\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}$

$=>\ k_2\ =\ 4k_1$

Hence, the kinetic energy will increase by 4 times.

7 0

2 years ago

Mary buys a reel of thread for sewing. There are 10 m of thread on the real. She uses 210 cm. How much is left on the reel in ce

babunello [35]

Answer:

the length of the thread remaining is 790 cm

Step-by-step explanation:

Given;

original length of the thread, L₀ = 10 m = 1000 cm

the length of the thread used, L₁ = 210 cm

The length of the thread remaining is calculated as follows;

ΔL = L₀ - L₁

ΔL = 1000 cm - 210 cm

ΔL = 790 cm

Therefore, the length of the thread remaining is 790 cm

5 0

2 years ago

Help pleasesolve for X​

Help pleasesolve for X