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navik [9.2K]
3 years ago
12

How do you solve [x^2(2x+3)]^3 ?

Mathematics
1 answer:
Bond [772]3 years ago
8 0

Answer:

here's the steps

Step-by-step explanation:

first of the numbers inside the [ ] is always positive.Now since the 3 is outside the [ ] you use it like a tool and don't change it, so nothing happen to it.since ^3 is missing a base (variable, cannot remember exact name) but is not missing ^3, which make them alike enough to multiply because 3 is outside of () nut the ^3 will stay the same (don't know why but that's how math works)

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7 = 3/4(3) + b
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so ur equation is : y = 3/4x + 19/4

if point A (x,5) lies on the line.....
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4/12 reduces to 1/3 = x......so point A is (1/3,5)...with x being 1/3
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