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Liono4ka [1.6K]
2 years ago
14

Find the x and y intercepts. 2x-4y=8

Mathematics
2 answers:
Zigmanuir [339]2 years ago
5 0
Hopefully this was helpful for you

ivanzaharov [21]2 years ago
4 0

Answer:

2

x

+

4

y

+

8

=

0

Step-by-step explanation:

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Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
2 years ago
1.) What is the relationship between sine & cosine?
Dmitry [639]
It's A ...cos (90- theta) = sin theta

so A
3 0
3 years ago
Each person needs to rent a helmet for $5. Write the expression for the total cost for the helmets
Artyom0805 [142]

Step-by-step explanation:

you need to find out how many poeple u have first

4 0
2 years ago
A pool measuring 10 meters by 26 meters is surrounded by a path of uniform​ width, as shown in the figure. If the area of the po
igomit [66]

Based on the measurements of the pool and the path of uniform width, the area of the width and length of the path can be found to be 28.8 meters.

<h3>How to find the width and length?</h3>

First, find the area of the pool:

= Length x Width

= 10 x 26

= 260 meters ²

The area of the path can therefore be found to be:

= Total area of pool and path combined - Area of pool

= 1,092 - 260

= 832 meters²

Seeing as the path has uniform width, that means that the width is the same and the length so the width and length of the pool is:
= √area of the path

= √832

= 28.8

In conclusion, the width and length of the path are 28.8 meters.

Find out more on combined area at brainly.com/question/12966430

#SPJ1

8 0
1 year ago
You want to buy carpet for your living room. The room is rectangular and the dimensions are 10 feet by 6 feet. How many square f
Paraphin [41]

Answer:

60 ft^2

Step-by-step explanation:

This is a problem where you calculate the area of a rectangle A=bh. b=10 and h=6 so A=6*10 or 60 ft^2

3 0
2 years ago
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