Answer: -1
Step-by-step explanation:
Subtract each fraction by each other than simplify
For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
Apparently there's no solution?? i tried solving it, and i also used a special calculator, but no solution came up
they are the same so set them equal
3x-10=2x+40 now combine like terms
3x-2x=40+10
x=50
Divide both sides by l. Hope this helps! :D
