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2 years ago

Find the x and y intercepts. 2x-4y=8

Mathematics

2 answers:

Zigmanuir [339]2 years ago

5 0

Hopefully this was helpful for you

ivanzaharov [21]2 years ago

4 0

Answer:

Step-by-step explanation:

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Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

7 0

2 years ago

1.) What is the relationship between sine & cosine?

Dmitry [639]

It's A ...cos (90- theta) = sin theta

so A

3 0

3 years ago

Each person needs to rent a helmet for $5. Write the expression for the total cost for the helmets

Artyom0805 [142]

Step-by-step explanation:

you need to find out how many poeple u have first

4 0

2 years ago

A pool measuring 10 meters by 26 meters is surrounded by a path of uniform width, as shown in the figure. If the area of the po

igomit [66]

Based on the measurements of the pool and the path of uniform width, the area of the width and length of the path can be found to be 28.8 meters.

<h3>How to find the width and length?</h3>

First, find the area of the pool:

= Length x Width

= 10 x 26

= 260 meters ²

The area of the path can therefore be found to be:

= Total area of pool and path combined - Area of pool

= 1,092 - 260

= 832 meters²

Seeing as the path has uniform width, that means that the width is the same and the length so the width and length of the pool is:
= √area of the path

= √832

= 28.8

In conclusion, the width and length of the path are 28.8 meters.

Find out more on combined area at brainly.com/question/12966430

#SPJ1

8 0

1 year ago

You want to buy carpet for your living room. The room is rectangular and the dimensions are 10 feet by 6 feet. How many square f

Paraphin [41]

Answer:

60 ft^2

Step-by-step explanation:

This is a problem where you calculate the area of a rectangle A=bh. b=10 and h=6 so A=6*10 or 60 ft^2

3 0

2 years ago