The circumference of the outer edge of the path around the pool is 113.04 ft.
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What is the circumference?</h3>
The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle. 
Given
A circular swimming pool has a radius of 15 ft. 
There is a path all the way around that pool that is three feet wide. 
A circle has a radius of 15 feet. 
A larger circle goes around the smaller circle that is 3 feet wide.
The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.
The radius of the outer edge of the path around the pool = 15 + 3 
The radius of the outer edge of the path around the pool = 18ft
The circumference of the outer edge of the path around the pool is;

Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.
To know more about circumference click the link given below.
brainly.com/question/5023328
 
        
             
        
        
        
Answer:
NOPE, NOT EQUAL!!
Step-by-step explanation:
 
        
             
        
        
        
Answer:
The answer is 2.
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Well she charged twice as much to walk large then small. Let s be small and l be large.
We we know that 
l = 2s
we also know that she wants to make 100 so
xl + ys = 100
Where where x is number of large and y is number of small. it says she walked 10 small and 5 large so
5l + 10s = 100
substitute 2s for l because they are same value as shown in first equation I made
5 (2s) + 10s = 100
10s + 10s = 100
20s = 100
s = 5
we can now solve for l
l = 2s
l = 2 * 5
l = 10
So s is 5 and l is 10.