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4 years ago

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find a counterexample to show that the following statment is false. if a number is multipled by itself, the result is even. choo

se the correct answer below a. 3*5=15 b. 6+6=12 c. 4*4=16 d. 5*5=25

1 answer:

olya-2409 [2.1K]4 years ago

7 0

A. Not a proper counterexample as 3 and 5 aren't the same number. We can rule out choice A.

B. We can rule out choice B since we're not multiplying here

C. We are multiplying the same value with itself but the result is even. We can rule this out.

D. This is a proper counter example. We have the same number (5) multiplied by itself leading to a result that is not even. It contradicts the initial claim.

Answer: Choice D

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Mice21 [21]

Answer: A: V is an acute angle, so it is less than 90 degrees. I would say it's around 45 degrees.

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Step-by-step explanation:

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4 years ago

WORTH 25 POINTS!!!!!!!!!!!!!!!!!!!!

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3 years ago

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Explain how you could find 3/8% of $800

Snezhnost [94]

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3 years ago

Make a table of values for f(x) = 18x2 + 10x + 1.

serg [7]

Answer/step-by-step explanation:

To make a table of values, substitute each value of x into the given equation function $f(x) = 18x^2 + 10x + 1$

For x = -3,

$f(-3) = 18(-3)^2 + 10(-3) + 1$

$f(-3) = 18(9) + (-30) + 1$

$f(-3) = 162 - 30 + 1 = 133$

For x = -2,

$f(-2) = 18(-2)^2 + 10(-2) + 1$

$f(-2) = 18(4) + (-20) + 1$

$f(-2) = 72 - 20 + 1 = 53$

For x = -1,

$f(-1) = 18(-1)^2 + 10(-1) + 1$

$f(-1) = 18(1) + (-10) + 1$

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For x = 0,

$f(0) = 18(0)^2 + 10(0) + 1$

$f(0) = 18(0) + 0 + 1$

$f(0) = 0 - 0 + 1 = 1$

For x = 1,

$f(1) = 18(1)^2 + 10(1) + 1$

$f(1) = 18(1) + 10 + 1$

$f(1) = 18 + 10 + 1 = 29$

For x = 2,

$f(2) = 18(2)^2 + 10(2) + 1$

$f(2) = 18(4) + 20 + 1$

$f(2) = 72 + 20 + 1 = 93$

For x = 3,

$f(3) = 18(3)^2 + 10(3) + 1$

$f(3) = 18(9) + 30 + 1$

$f(3) = 162 + 30 + 1 = 193$

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3 years ago

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nekit [7.7K]

Step-by-step explanation:

94 is the perimeter i think ..... ............

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3 years ago