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2 years ago

Look at the data in the table.

Mathematics

1 answer:

Amiraneli [1.4K]2 years ago

5 0

Okay then what, what do you want help with

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4 bottles of water cost 10 dollars at a music festival.

TiliK225 [7]

Answer:

7 dollars and 50 cents, price per bottle is 2 dollars (you can get this answer by dividing 10/4) and 50 cents multiply that by 3 and you get the answer, 7 dollars and 50 cents.

Step-by-step explanation:

I believe this is correct, if not feel free to let me know and I will fix it. I'm sorry in advance if it is incorrect.

6 0

2 years ago

Classify the product as a whole number

ch4aika [34]

Let's solve for the answer to determine if it is rational.

$\frac{-2 \frac{2}{5} }{-4}=12/5/4= \frac{3}{5} 


$ it is a rational number.

4 0

2 years ago

On a coordinate plane, a triangle is shown. It has points A prime (4, 2), B prime (8, negative 8), and C prime (4, negative 8).

gogolik [260]

Answer: A

Explaining: Because A actually shows all the steps and work. And it’s the more realest android.

4 0

2 years ago

Read 2 more answers

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

2 years ago

If x equals -3. find the matching value for y. 2x-3y=6

tiny-mole [99]

-4

Step-by-step explanation:

2(-3)-3y=6

-6-3y=6

-3y=12

y=-4

if I helped you, please vote brainliest

7 0

2 years ago