Answer:
(i) 4000
(ii) $5.00
Step-by-step explanation:
Let no. of shares of Company A be X
Let share price of Company B on Day 7 be $y
Share price of Company B on Day 12 = $(y-0.50)
(i)
Consider Day 7:
4.60x - 2000y = 7400................ (1)
Consider Day 12:
4.80x - 5000(y-0.50) = -5800
4.80x - 5000y + 2500 = -5800
4.80x - 5000y = -8300............... (2)
(1)*2.5:
11.5x - 5000y = 18500................. (3)
(3)-(2):
11.5x - 4.80x - 5000y + 5000y = 18500 + 8300
6.70x = 26800
x = 4000
(ii)
Sub. x = 4000 into (1):
4.60(4000) - 2000y = 7400
-2000y = 7400 - 18400
-2000y = -11000
y = 5.5
Share price of Company B on Day 12
= 5.50 - 0.50
= $5.00
Answer: 210 advanced tickets were sold. 130 same day tickets were sold.
Step-by-step explanation:
x= advanced tickets y=same day tickets
2x+3y=810 this equation represents the money
x+y=340 this equation represents the total number of tickets
x+y=340
<u>-x -x</u>
y=-340-x 2x+3(340-x)=810 210+y=340
2x+1020-3x=810 <u> -210 -210 </u>
-x+1020=810 y=130
<u> -1020 -1020</u>
<u>-x</u>=-<u>210</u>
-1 -1
x=210
Answer:82.24 meters were on each roll
Step-by-step explanation: 411.2/5=82.24
Answer:
n(n+1)
This is the answer I know
I think what the teacher wants is 15 which is the greatest common factor of all three numbers and the factors of 15 are
1 x 15 and 3 x 5 so the she can put one of each, or she can put 3 of each,
or she can put 5 of each , or she can put 15 of each.
The problem is unclear however because as worded she could put 2 sweaters, 2 shirts and 2 pair of jeans. I think the teacher wants all the jeans used. The number 1,3,5 and 15 will use up all of the jeans.
1 jean on 15 racks
or 3 jeans on 5 racks
or 5 jeans on 3 racks
or 15 jeans on one rack