If your team consisted of only you, your sister, and your mother, then your mother would have lost 17 pounds, and your sister would have lost 18 pounds.
Answer:
A: Yes, I agree. Why? Because if you look at the shape, its a triangle right, and a triangle both sides are equal, while the bottom line is not. But because both sides are equal, and half of the triangle is MPN and the other side is QPN, they both are congruent (or equal to)
B: Like I said, both MPN and QPN are both equal, and if you remove the P, it would still be the same because the shape has not changed.
I hope I helped :)
We have been given two points.
and
. We are asked to find the point B such that it divides line segment AC so that the ratio of AB to BC is 4:1.
We will use segment formula to solve our given problem.
When a point P divides segment any segment internally in the ratio
, then coordinates of point P are:
![[\right x=\frac{mx_2+nx_1}{m+n},y=\frac{my_2+ny_1}{m+n}\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D%5Cfrac%7Bmx_2%2Bnx_1%7D%7Bm%2Bn%7D%2Cy%3D%5Cfrac%7Bmy_2%2Bny_1%7D%7Bm%2Bn%7D%5Cleft%5D)
and
.

Upon substituting our given information in above formula, we will get:
![[\right x=\frac{4(3)+1(3)}{4+1},y=\frac{4(9)+1(4)}{4+1}\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D%5Cfrac%7B4%283%29%2B1%283%29%7D%7B4%2B1%7D%2Cy%3D%5Cfrac%7B4%289%29%2B1%284%29%7D%7B4%2B1%7D%5Cleft%5D)
![[\right x=\frac{12+3}{5},y=\frac{36+4}{5}\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D%5Cfrac%7B12%2B3%7D%7B5%7D%2Cy%3D%5Cfrac%7B36%2B4%7D%7B5%7D%5Cleft%5D)
![[\right x=\frac{15}{5},y=\frac{40}{5}\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D%5Cfrac%7B15%7D%7B5%7D%2Cy%3D%5Cfrac%7B40%7D%7B5%7D%5Cleft%5D)
![[\right x=3,y=8\left]](https://tex.z-dn.net/?f=%5B%5Cright%20x%3D3%2Cy%3D8%5Cleft%5D)
Therefore, the coordinates of point B would be
.
A)
= 3 2/4
= 3 1/2
b)
= 7 10/15 + 2 3/15
= 9 13/15
Let's start from what we know.

Note that:

(sign of last term will be + when n is even and - when n is odd).
Sum is finite so we can split it into two sums, first

with only positive trems (squares of even numbers) and second

with negative (squares of odd numbers). So:

And now the proof.
1) n is even.
In this case, both

and

have

terms. For example if n=8 then:

Generally, there will be:

Now, calculate our sum:



So in this case we prove, that:

2) n is odd.
Here,

has more terms than

. For example if n=7 then:

So there is

terms in

,

terms in

and:

Now, we can calculate our sum:




We consider all possible n so we prove that: