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Mandarinka [93]
3 years ago
8

basketball is played on a rectangular court in which the length is 2m less than twice the width. if the perimeter of the court i

s 86m, what are the dimensions of the court?​
Mathematics
1 answer:
Afina-wow [57]3 years ago
3 0

Answer:

length is 28 meters

width is 15 meters

Step-by-step explanation:

Write out formulas and assign variables:

Width: w

Length: l = 2w - 2

Here is a diagram:

<u>             2w - 2               </u>

|                                     |  w

|_________________|

The perimeter formula for rectangle is P = 2(l +w). Substitute the perimeter and the formula for length into the formula.

P = 2(l +w)

86 = 2(2w - 2 + w)       Simplify inside the brackets

86 = 2(3w - 2)            Divide both sides by 2

43 = 3w - 2              Add 2 to both sides

45 = 3w                  Divide both sides by 3

w = 45/3               Variable on left side is standard formatting

w = 15                 Width of basketball court

Substitute width into the length formula to fin length.

l = 2w - 2

l = 2(15) - 2

l = 30 - 2

l = 28           Length of basketball court

Therefore the length is 28 meters and the width is 15 meters.

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