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Lyrx [107]
3 years ago
13

Timothy evaluated the expression using x = 3 and y = –4. xy-2 3x2y−4

Mathematics
1 answer:
Leviafan [203]3 years ago
8 0
The expression xy-2, when x=3 and y= -4, becomes    (3)(-4)-2, or -14 (answer)

the expresion 3x^2*y - 4 becomes 3(3)^2*(-4) - 4, or 27(-4) - 4, or -108 - 4 = -112 (answer)

Leave Timmy out of this, since it seems he didn't really do anything.    ;)

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Answer:

Given: Two Isosceles triangle ABC and Δ PBC having same base BC. AD is the median of Δ ABC and PD is the median of Δ PBC.

To prove: Point A,D,P are collinear.

Proof:

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In Δ ABD and Δ ACD

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Similarly, Δ PBD ≅ Δ PCD [By SSS]

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But,  ∠1+∠2+ ∠ 3 + ∠4 =360° [At a point angle formed is 360°]

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CASE 2.

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PB=PC[given]

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BD =DC [Median of a triangle divides the side in two equal parts]

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Similarly, By proving ΔADB≅ΔADC we will get,  ∠ADB=∠ADC[CPCT]

As PD and AD are medians to same base BC of ΔPBC and ΔABC.

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