Answer:
0.7611 = 76.11% probability that the weight of a randomly selected steer is less than 1140lbs.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 900, \sigma = 300](https://tex.z-dn.net/?f=%5Cmu%20%3D%20900%2C%20%5Csigma%20%3D%20300)
Find the probability that the weight of a randomly selected steer is less than 1140lbs.
This is the pvalue of Z when X = 1140. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{1140 - 900}{300}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B1140%20-%20900%7D%7B300%7D)
![Z = 0.71](https://tex.z-dn.net/?f=Z%20%3D%200.71)
has a pvalue of 0.7611
0.7611 = 76.11% probability that the weight of a randomly selected steer is less than 1140lbs.
An expression is undefined when you divide by zero. A simple example is 1/0 which in english is "one over zero"
You cannot have zero in the denominator. Something like 0/1 is allowed as it is equal to 0. In other words, 0/1 = 0. But 1/0 is not allowed.
Answer:
option a and d
Step-by-step explanation:
![\frac{3}{4} = \frac{2x - 1}{2y + 4} \\ 3(2y + 4) = 4(2x - 1) \\ 6y + 12 = 8x - 4 \\ now \\ 6y = 8x - 4 - 12 \\ 6y = 8x - 16 \\ y = \frac{8x - 16}{6} \\ y = \frac{8x}{6} - \frac{16}{6} \\ y = \frac{4x}{3} - \frac{8}{3} \\ y = \frac{4}{3} x - \frac{8}{3} \\a nd \\ \\ 6y + 12 = 8x - 4 \\ 6y + 12 + 4 = 8x \\ 6y + 16 = 8x \\ \frac{6y + 16}{8} = x \\ \frac{6y}{8} + \frac{16}{8} = x \\ \frac{3y}{4} + 2 = x \\ x = \frac{3}{4} y + 2](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20%20%3D%20%20%5Cfrac%7B2x%20-%201%7D%7B2y%20%2B%204%7D%20%5C%5C%203%282y%20%2B%204%29%20%3D%204%282x%20-%201%29%20%5C%5C%206y%20%2B%2012%20%3D%208x%20-%204%20%5C%5C%20now%20%5C%5C%206y%20%3D%208x%20-%204%20-%2012%20%5C%5C%206y%20%3D%208x%20-%2016%20%5C%5C%20y%20%3D%20%20%5Cfrac%7B8x%20-%2016%7D%7B6%7D%20%5C%5C%20%20%20y%20%3D%20%20%5Cfrac%7B8x%7D%7B6%7D%20%20-%20%20%5Cfrac%7B16%7D%7B6%7D%20%20%5C%5C%20y%20%3D%20%20%5Cfrac%7B4x%7D%7B3%7D%20%20-%20%20%5Cfrac%7B8%7D%7B3%7D%20%20%5C%5C%20y%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%20x%20-%20%20%5Cfrac%7B8%7D%7B3%7D%20%20%5C%5Ca%20nd%20%5C%5C%20%20%5C%5C%206y%20%2B%2012%20%3D%208x%20-%204%20%5C%5C%20%206y%20%2B%2012%20%2B%204%20%3D%208x%20%5C%5C%206y%20%2B%2016%20%3D%208x%20%5C%5C%20%20%5Cfrac%7B6y%20%2B%2016%7D%7B8%7D%20%20%3D%20x%20%5C%5C%20%20%5Cfrac%7B6y%7D%7B8%7D%20%20%20%2B%20%20%5Cfrac%7B16%7D%7B8%7D%20%20%3D%20x%20%5C%5C%20%20%5Cfrac%7B3y%7D%7B4%7D%20%20%2B%202%20%3D%20x%20%5C%5C%20%20x%20%3D%20%5Cfrac%7B3%7D%7B4%7D%20y%20%2B%202)
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