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sertanlavr [38]
3 years ago
15

Every two days he’s trying to spend 1.75 hours observing dolphins and 2.5 hours observing sea lines at this rate how many total

hours will the scientist spend a observing dolphins and sea lions in 10 days
Mathematics
1 answer:
inysia [295]3 years ago
5 0
The scientist was observing for 42.5 hours.





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Three brothers, Justin, Jared, and Jonathan decided to buy a present for their mom's birthday. Justin gave decided to spend 1/4
iVinArrow [24]
I believe that, if there are three brothers and each invested the same exact money to make a total of $33.00, each brother would have invested $11.

Jonathan's was different, as he invested 2/5. 11 divided by 2 is 5.5, in which 5.5*11 would equal 27.50.
The rest was simply their denominator times $11.
Jared had $33 dollars before the investment, and Justin has $44.
7 0
2 years ago
Can someone help me with this?
Natasha2012 [34]

Answer: X can not be 11 or higher, so that means this problem will be 10 or lower. There for the value of X=6

Step-by-step explanation:

4 0
3 years ago
Ginny is studying a population of frogs. She determines that the population is decreasing at an average rate of 3% per year. Whe
svp [43]

Answer:

Step-by-step explanation:

This is exponential, of the form

y=a(b)^x where a is the initial amount and b is the growth/decay rate. If Ginny begins the study with 1200 frogs in the population, our a value is 1200.

If the population is decreasing 3% per year, it is decreasing 100% - 3% = 97% which, as a decimal, is .97. Our exponential function, then, is

y=1200(.97)^x

6 0
2 years ago
Solve each system using substitution: 7x-2y=1 2y=x-1
Mrrafil [7]
Hello :
<span>7x-2y=1 ...(1)
 2y=x-1...(2)
</span><span>substitution  2y in (1) :
</span>7x-(x-1) = 1
7x-x+1 = 1 
7x = 0
x=0
in (2) :   2y = 0-1
2y = -1        y=  -1/2
the <span>system have one solution :  (0 ;-1/2)</span>
7 0
2 years ago
Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 42-m-42-m squar
oee [108]

The area enclosed by the figure is 4533.48 square meters.

<u>Step-by-step explanation:</u>

Side length of the square = 42m

The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.

Radius of the semicircle = 21m

Area of the square = 42 x 42 = 1764 square meters

Area of 1 semicircle = π(21 x 21) /2

= (3.14) (441) /2

= 1384.74/2

= 692.37 square meters

Area of 4 semicircle = 4 x 692.37

= 2769.48 square meters

Total area = 1764 + 2769.48

= 4533.48 square meters

The area enclosed by the figure is 4533.48 square meters.

7 0
2 years ago
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