The function f(x) = −(x + 5)(x + 1) is shown. On a coordinate plane, a parabola opens down. It goes through (negative 5, 0), has

Question

4 years ago

3

The function f(x) = −(x + 5)(x + 1) is shown. On a coordinate plane, a parabola opens down. It goes through (negative 5, 0), has

a vertex at (negative 3, 4), and goes through (negative 1, 0). What is the range of the function? all real numbers less than or equal to 4 all real numbers less than or equal to −3 all real numbers greater than or equal to 4 all real numbers greater than or equal to −3

Mathematics

2 answers:

stepladder [879] · Answer 1 · 2022-01-01T01:01:19+03:00

Answer:

The range is all real numbers less than or equal to 4

Step-by-step explanation:

we have

$f(x)=-(x+5)(x+1)$

This is a vertical parabola open downward

The vertex is a minimum

The vertex is the the point (-3,4)

The x-intercepts are x=-5, x=-1

The domain is the interval -----> (-∞,∞)

The domain is all real numbers

The range is the interval ----> (-∞, 4]

The maximum value of the range is the y-coordinate of the vertex

$y\leq 4$

The range is all real numbers less than or equal to 4

krok68 [10] · Answer 2 · 2022-01-01T02:29:48+03:00

krok68 [10]4 years ago

3 0

Answer:

The range is all real numbers less than or equal to 4

Step-by-step explanation:

Just took the test.