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igor_vitrenko [27]
3 years ago
6

What part of 3 12 is 1/2 ? I need this asap

Mathematics
1 answer:
Aliun [14]3 years ago
6 0
I assume you are asking one of three things, so I will answer all of them.

if you are asking what is 1/2 of 312, then multiply 312 by 1/2. 312 is really just 312/1, so
312 \times  \frac{1}{2}  =  \frac{312}{1}  \times  \frac{1}{2}
we multiply fractions by multiplying straight across
\frac{312 \times 1}{1 \times 2}  =  \frac{312}{2}  = 156


if you were asking what part of 3 1/2 is 1/2 then we have to recognize what 3 1/2 is as an improper fraction. to do this, we convert 3 into halves. how many halves of pizza are there in 3 whole pizzas? 6. so we have 6 halves and one half, which is a total of 7 halves.
\frac{6}{2}  +  \frac{1}{2}  =  \frac{7}{2}
now, we do the same thing as the first problem
\frac{7}{2}  \times  \frac{1}{2}  =  \frac{7 \times 1}{2 \times 2}  =  \frac{7}{4}

if you were asking what is half of 3.12, then we convert 1/2 to a decimal and multiply
\frac{1}{2}  = .5 \\ 3.12 \times .5 = 1.56
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The force F (in newtons) of the hydraulic cylinder in a press is proportional to the square of sec x where x is the distance (in
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Part A) F(x) =500 sec(x)

Part B) Average force exerted by the press = 750 N

Step-by-step explanation:

Given:

F(x) ∝ sec(x)

Range of x = [0,Pi/3] or x = [0 , 60°]

F(0) = 500 N i.e. F is 500 N at x = 0.

As we now that:

Force is proportional to sec(x) therefore we may write an equation by introducing Proportionality Constant (k) as under:

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Then using given information of F=500 N at x = 0 we have:

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F(x) = 500 * sec(x)

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F(Pi/3) = 500 * sec(Pi/3)

As Pi = 180 there we simplify the above equation as:

F(60°) = 500 * sec(60°)

F(60°) = 500 * 2 ; By putting sec(60°) = 2

F(60°) = 1000 N

Now the avg. of force exerted by the hydraulic press is given by:

Avg. Force = Minimum Force + [(Maximum Force - Minimum Force) / 2] - Say it equation 2

Considering sec(x) is minimum at x = 0 and maximum at x = 60° within the given range [0 , 60°] therefore we have:

The minimum force being put at x = 0 i.e. F = 500 N and max. force at x = 60° which is F = 1000 N.

Finally we get the average force using equation 2 as under:

Average force = 500 +  [(1000 - 500) / 2]

Average Force = 500 + 250

Average Force = 750 N

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