All categories

3 years ago

Work out the size of angle a AB = 11cm AC = 9cm

Mathematics

1 answer:

Papessa [141]3 years ago

8 0

Step-by-step explanation:

simply use trig ( cos)

so cosx°= 9/11

now do cos^-1 x°(9/11) in a calculator to find the value of the angle

that will result in 35.09°

You might be interested in

Solve for x: <br><br> 2 + 8 - x = -24 =?

gregori [183]

Answer:

x = 34

Step-by-step explanation:

Add x+24 to both sides of the equation and simplify.

2 + 8 - x + x + 24 = -24 + x + 24

34 = x

7 0

3 years ago

Are the graphs of the lines in the pair parallel? Y=-2/3x -18<br> -6x -9y=18

zvonat [6]

Yes for when you solve the problem then graph it.

5 0

3 years ago

A man invests his savings in two accounts ,one paying6% and the other paying 10% simple interest per year. He puts twice as much

AnnyKZ [126]

Answer: he invested $46062.5 at 6% and $23031.25 at 10%

Step-by-step explanation:

Let x represent the amount which he invested in the account paying 6% interest.

Let y represent the amount which he invested in the account paying 10% interest.

He puts twice as much in the lower-yielding account because it is less risky.. This means that

x = 2y

The formula for determining simple interest is expressed as

I = PRT/100

Considering the account paying 6% interest,

P = $x

T = 1 year

R = 6℅

I = (x × 6 × 1)/100 = 0.06x

Considering the account paying 10% interest,

P = $y

T = 1 year

R = 10℅

I = (y × 10 × 1)/100 = 0.1y

His annual interest is $7370dollars. it means that

0.06x + 0.2y = 7370 - - - - - - - - - -1

Substituting x = 2y into equation 1, it becomes

0.06 × 2y + 0.2y = 7370

0.12y + 0.2y = 7370

0.32y = 7370

y = 7370/0.32

y = $23031.25

x = 2 × 23031.25

x = 46062.5

6 0

3 years ago

AB=diameter of the circle O. OC=radius. Arc AXB is an arc of the circle with centre C. Prove areas of the shaded region are =

alexandr1967 [171]

1.
Draw a circle with center C And radius CA, as shown in the attached picture.

Let the lengths of radii AO, OB, OC be R. Triangle ABC is inscribed in the circle with center O and one of its sides is a diameter, this means that the angle ACB is a right angle.
|AO|=|OC|=R, by the Pythagorean theorem |AC|= $\sqrt{2}R$ .

these are all shown in the picture.

2.

Area of triangle ABC is 1/2 * 2R * R= R^2

3.

Let the area between arc BXA and chord AB be Y. (the yellow region).

and let G be the shaded region between arcs AB and AXB.

G=1/2(Area circle with center O)-Y
= $\frac{1}{2} \pi R^{2}-Y$

To find Y:

Notice that the area of the sector ACB is 1/4 of the area of circle with center C, since m(ACB) is 1/4 of 360 degrees.

So Area of sector ACB = $\frac{1}{4} \pi (\sqrt{2} R)^{2}=\frac{1}{4} \pi*2 R^{2} =\frac{1}{2} \pi R^{2}$

Y =area of sector ABC-Area(triangle ABC)= $\frac{1}{2} \pi R^{2}- \frac{1}{2}*2R*R=\frac{1}{2} \pi R^{2}- R^{2}$

4.

Finally,

$G=\frac{1}{2} \pi R^{2}-Y=\frac{1}{2} \pi R^{2}-(\frac{1}{2} \pi R^{2}- R^{2})=R^{2}$

This proves that the 2 shaded regions have equal area.

5 0

3 years ago

I'm not that smart with this stuff so, please help?

muminat

The product is 7/12 6

5 0

3 years ago