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3 years ago

What is the common difference between successive terms in the sequence

Mathematics

1 answer:

Lelechka [254]3 years ago

4 0

9,2.5,-4,-10.5,-17

Let's find the difference between two consecutive terms

2.5 - 9 = -6.5

-4 - 2.5 = -6.5

-10.5 - (-4) = -6.5

-17 -(-10.5) = -6.5

We can see that the common difference is -6.5

-6.5 is the common difference between successive terms in the sequence 9,2.5,-4,-10.5,-17

the common difference is negative because we subtract 6.5 to get the next term.

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An accounting firm purchased a new digital camera that cost $2,500. The life of the camera is estimated to be 5 years. The total

lozanna [386]

2500-700 = 1800
1800/5 = 360

The annual depreciation of the camera is $360.

5 0

3 years ago

Please answer all

vladimir1956 [14]

Step-by-step explanation:

b) y=x+1

table:

_x _|_2x_|_y_|(x, y)|

0 |2(0) |1 |(0, 1)|

1 | 2(1) |2 |(1, 2)|

2 | 2(2) |3 |(2, 3)|

3 | 2(3) |4 |(3, 4)|

c) y=3x+2

_x _|_2x_|_y_|(x, y)|

0 |2(0) |2 |(0, 2)|

1 | 2(1) |5 |(1, 5)|

2 | 2(2) |8 |(2, 8)|

3 | 2(3) |14 |(3, 14)|

To graph, plot the x, y points and connect all of them

7 0

3 years ago

50 points but please give a helpful answer <3

Rasek [7]

They are all (SAS)side angle side except for the bottom right one. This is because the question does not give the little ticks to show that one side is the same as the other. It is not good enough to assume they are congruent without proof.

8 0

3 years ago

A line for tickets to a Broadway show had a mean waiting time of 20 minutes with a standard deviation of 5 minutes.

andrezito [222]

Answer:

5.48% of the people in line waited for more than 28 minutes

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean waiting time of 20 minutes with a standard deviation of 5 minutes.

This means that $\mu = 20, \sigma = 5$

What percentage of the people in line waited for more than 28 minutes?

The proportion is 1 subtracted by the p-value of Z when X = 28. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{28 - 20}{5}$

$Z = 1.6$

$Z = 1.6$ has a p-value of 0.9452.

1 - 0.9452 = 0.0548.

As a percentage:

0.0548*100% = 5.48%

5.48% of the people in line waited for more than 28 minutes

6 0

3 years ago

Consider the following piecewise-defined function, find f(-4)

My name is Ann [436]

F(-4)=11...because x is less than 3, you use the top one.

8 0

3 years ago

What is the common difference between successive terms in the sequence​

What is the common difference between successive terms in the sequence