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3 years ago

Please help urgent ! trig !

Mathematics

1 answer:

attashe74 [19]3 years ago

3 0

Answer:

Sin = 6/7

cos = sqrt(13)/7

sec = 7sqrt(13) / 13

Step-by-step explanation:

First find the unknown side length using the pythagorean theorem (it equals 3sqrt(13))

Sin is opposite over hypotenuse, so it would be 18/21 or 6/7

Cos is adjacent over hypotenuse, so it would be 3sqrt(13) / 21 or sqrt(13)/7

Sec is the reciprocal of the cos, so it would be 7/sqrt(13). However, the answer is 7sqrt(13)/13 because we rationalized our bases.

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Find the rational roots f(x) =3x3+ 2x2 + 3x + 6

Ann [662]

The rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

<h3>How to determine the rational root of the function f(x)?</h3>

The function is given as:

f(x) = 3x^3 + 2x^2 + 3x + 6

For a function P(x) such that

P(x) = ax^n +...... + b

The rational roots of the function p(x) are

Rational roots = ± Possible factors of b/Possible factors of a

In the function f(x), we have:

a = 3

b = 6

The factors of 3 and 6 are

a = 1 and 3

b = 1, 2, 3 and 6

So, we have:

Rational roots = ±(1, 2, 3, 6)/(1, 3)

Split the expression

Rational roots = ±(1, 2, 3, 6)/1 and ±(1, 2, 3, 6)/3

Evaluate the quotient

Rational roots = ±(1, 2, 3, 6, 1/3, 2/3, 1, 2)

Remove the repetition

Rational roots = ±(1, 2, 3, 6, 1/3, 2/3)

Hence, the rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

The complete parameters are:

The function is given as:

f(x) = 3x^3 + 2x^2 + 3x + 6

The rational roots of f(x) = 3x^3 + 2x^2 + 3x + 6 are ±(1, 2, 3, 6, 1/3, 2/3)

Read more about rational roots at

brainly.com/question/17754398

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Yuliya22 [10]

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3 years ago

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makvit [3.9K]

Answer:

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