All categories

3 years ago

Order these from least to greatest: 4/7, 1/3, 2/10

Mathematics

1 answer:

yan [13]3 years ago

6 0

Answer:

2/10, 4/7, 1/3

Step-by-step explanation:

You might be interested in

A survey asked a group of students to choose their favorite type of snack. The results of the survey are shown in the graph.

Pavlova-9 [17]

30 students.

5 + 2 + 4 + 7 + 5 + 9 = 32 students

<span>192 students. 32 students</span> = 6

so,

7 − 2 = 5

5 students × 6 = 30 students

4 0

3 years ago

Read 2 more answers

Supply the missing reasons to complete the proof.

MAXImum [283]

Answer:

3. ASA

4. Corresponding sides of congruent triangles are congruent

Step-by-step explanation:

I marked this in the attached image. ∠B ≅∠E, ∠ACE ≅ ∠DCE, and the side between them BC ≅ EC, so the the triangles ΔACB and ΔDCE are congruent by ASA.

If the triangles are congruent, then all corresponding angles and sides are also congruent.

7 0

2 years ago

Which expression is equivalent to 15 - 5x? select all that apply

m_a_m_a [10]

Choices A and B are correct. To find the equivalent expressions, you would do the distributive property for the choices to
get rid of the parentheses. You would then see which choices match up with 15 - 5x. Hope this helps!
A.) -5x + 15 (yes)
B.) 15 - 5x (yes)
C.) -15 + 5x (no)
D.) 5 - x (no)

3 0

3 years ago

Solve by elimination:<br> 2x + 4y = 34<br> x+4y = 27<br> A (7,-5)<br> B (6,6)<br> (7,5)<br> (5,7)

julsineya [31]

Answer:

(7,5)

Step-by-step explanation:

{2x + 4y = 34

{4y = 27 - x

2x + 27 - x = 34

x=7

4y = 27 - 7

y = 5 so the answer is ( 7,5)

3 0

3 years ago

Read 2 more answers

Two forces with magnitudes of 150 and 100 pounds act on an object at angles of 30° and 120°, respectively. Find the direction an

lyudmila [28]

<h2>Answer:</h2>

$Magnitude=180.27 \ lbf \\ \\ Direction=63.69 \ degrees$

<h2>Step-by-step explanation:</h2>

We have two forces as follows:

<u>First force:</u>

Magnitude: 150 pounds

Angle: 30°

<u>First force:</u>

Magnitude: 100 pounds

Angle: 120°

So the components can be found as follows:

$F_{1x}=150cos(30)=129.90 \ lbf\\F_{1y}=150sin(30) = 75 \ lbf \\ \\ F_{2x}=100cos(120)=-50 \ lbf\\F_{2y}=100sin(120) = 86.60 \ lbf$

So the components of the resultant force can be found by adding each component of the individual forces as follows:

$R_{x}=\Sigma F_{x} \\ R_{y}=\Sigma F_{y} \\ \\ R_{x}=129.90-50=79.90 \ lbf \\ R_{y}=75+86.60=161.6 \ lbf$

Finally, the magnitude and direction of the resultant force is:

$Magnitude \rightarrow R=\sqrt{R_{x}^2+R_{y}^2}=\sqrt{79.90^2+161.6^2}=180.27 \ lbf \\ \\ Direction \rightarrow \theta=tan^{-1}(\frac{R_{y}}{R_{x}})=tan^{-1}(\frac{161.6}{79.90})=63.69 \ degrees$

6 0

3 years ago

Read 2 more answers