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3 years ago

Pls PLS solve T_T i tried everything

Mathematics

2 answers:

Rudik [331]3 years ago

6 0

Answer:

12√3 is the correct answer

expeople1 [14]3 years ago

6 0

Let AO intersect BC at D

ΔAOB = ΔBOC = ΔAOC (SAS)

AB = BC = AC

ΔABC is equilateral

O is the circumcenter of equilateral ΔABC

Therefore, O is also the centroid of ΔABC

AO / AD = 2/3

2 $\sqrt{3}$ / AD = 2/3

AD = 3 $\sqrt{3}$

Right triangle ADB has ∠ABD = 60°

AB / AD = 2/ $\sqrt{3}$

AB / 3 $\sqrt{3}$ = 2/ $\sqrt{3}$

AB = 6

Perimeter of ΔABC = 6 + 6 + 6 =18

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Answer:

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Step-by-step explanation:

8*25=2.00

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3 years ago

In ΔUVW, the measure of ∠W=90°, the measure of ∠V=71°, and VW = 55 feet. Find the length of UV to the nearest tenth of a foot.

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7 0

3 years ago

Does anyone know this?

Neko [114]

"c" is the hypotenuse of the largest triangle, and "a" is that triangle's shortest side. Thus the ratio is

... (longest side)/(shortest side)

Since all the triangles in the figure are similar, to complete the proportion, you need to recognize the triangle that "a" is the longest side of, then find the shortest side of that triangle.

"a" is the longest side (hypotenuse) of the smallest triangle. The shortest side of that triangle is "r". So, your proportion is ...

... c/a = a/r

The appropriate choice is the 2nd one, ...

... r

8 0

3 years ago

What is a theoretical temperature at which the motion of all atoms and molecules stops; the coldest possible temperature? *

svetoff [14.1K]

B is the answer
Mark as brainlessness

5 0

3 years ago

The Ohio Department of Agriculture tested 203 fuel samples across the state in 1999 for accuracy of the reported octane level. F

OlgaM077 [116]

Answer:

The Sample size is 1918.89035

Step-by-step explanation:

Consider the provided information.

It is given that 14 out of 105 samples failed.

Therefore p = 14/105 = 0.13 3... and q=1-0.133=0.867

Samples would be needed to create a 99 percent confidence interval.

Subtract the confidence level from 1, then divide by two.

$\frac{(1 -0.99)}{2}=0.005$

By standard normal table z=2.5758≈2.58

Calculate the sample size as:

$n=\frac{z^2pq}{e^2}$

Where, e is the margin of error,

Substitute the respective values.

$n=\frac{(2.58)^2(0.133)(0.867)}{(0.02)^2}=1918.89$

Hence, the Sample size is 1918.89035

4 0

3 years ago

Pls PLS solve T_T i tried everything ​

Pls PLS solve T_T i tried everything