Question

Pls PLS solve T_T i tried everything ​

Answer 1

Answer:

12√3 is the correct answer

Answer 2

Let AO intersect BC at D

ΔAOB = ΔBOC = ΔAOC (SAS)

AB = BC = AC

ΔABC is equilateral

O is the circumcenter of equilateral ΔABC

Therefore, O is also the centroid of ΔABC

AO / AD = 2/3

2$\sqrt{3}$ / AD = 2/3

AD = 3$\sqrt{3}$

Right triangle ADB has ∠ABD = 60°

AB / AD = 2/$\sqrt{3}$

AB / 3$\sqrt{3}$ = 2/$\sqrt{3}$

AB = 6

Perimeter of ΔABC = 6 + 6 + 6 =18