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3 years ago

Pls PLS solve T_T i tried everything

Mathematics

2 answers:

Rudik [331]3 years ago

6 0

Answer:

12√3 is the correct answer

expeople1 [14]3 years ago

6 0

Let AO intersect BC at D

ΔAOB = ΔBOC = ΔAOC (SAS)

AB = BC = AC

ΔABC is equilateral

O is the circumcenter of equilateral ΔABC

Therefore, O is also the centroid of ΔABC

AO / AD = 2/3

2 $\sqrt{3}$ / AD = 2/3

AD = 3 $\sqrt{3}$

Right triangle ADB has ∠ABD = 60°

AB / AD = 2/ $\sqrt{3}$

AB / 3 $\sqrt{3}$ = 2/ $\sqrt{3}$

AB = 6

Perimeter of ΔABC = 6 + 6 + 6 =18

You might be interested in

Suppose the diameter of a circle is 6 units What is its circumference?

Kipish [7]

Answer:

18.84 estimated, 6π exactly

Step-by-step explanation:

Hi!

<u>The formula for finding the circumference of a circle is 2πr:</u>

In that case, all we need to do <em>first </em>is to divide the diameter by 2, so we can substitute that into the equation.

6 ÷ 2 = 3

So we have 2π × 3 to solve.

2π × 3 = 6π

We can estimate the circumference by multiplying by 3.14.

6 × 3.14 = 18.84

(actually multiplying by π gives 18.849... which is pretty close!)

Thus, the circumference is $\boxed{6\pi{\text{\:or\:18.84\:roughly}}}$ .

Hope this helps!

6 0

2 years ago

How many L of an 85% alcohol solution must be mixed with 6 L of a 55% alcohol solution to make a 65% solution?

zepelin [54]

Answer:

3 Liters of the 85% Solution

Step-by-step explanation:

You have to draw your buckets. I can't on computer so imagine the fraction bar is the bottom of the buckets.

$\frac{85}{x}+\frac{55}{6}=\frac{65}{x+6}$

Then we multiply the top of the buckets with the bottom:

85x+330=65x+390

Now we simplify and solve

20x=60

x=3

You need 3 liters of the 85% solution!

4 0

3 years ago

The force of gravity on Mars is different than on Earth. The function of the same situation on Mars would be represented by the

sweet-ann [11.9K]

Answer:

If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.

Step-by-step explanation:

Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:

$v=v_0+a\,*\,t\\y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2$

the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.

Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:

$v=v_0+a\,*\,t\\0=v_0-g\,*\,t\\t=\frac{v_0}{t}$

When we use this to replace the 't" in the displacement formula, we et:

$y-y_0=v_0\,* t + \frac{1}{2} a\,\,t^2\\y-y_0=v_0\,(\frac{v_0}{g} )-\frac{g}{2} \,(\frac{v_0}{g} )^2\\y-y_0=\frac{1}{2} \frac{v_0^2}{g}$

This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)

And we can also answer the question about time, since given the same initial velocity $v_0$ , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)