Find the missing term of 3b2 − = -9b2 ? -6b^2 -9b^2 -12b^2

Mathematics

1 answer:

gladu [14]3 years ago

7 0

3b^2 - x = -9b^2
x = 3b^2 +9b^2

x = 12b^2

3b^2 -12b^2 = -9b^2

hope this will help you

You might be interested in

The sum of six times a number and thirteen is five less than the product of three and the number

Svetllana [295]

Answer:

1 and 1/3

Step-by-step explanation:

I got this because you can first take 13-5 which is 8 then you can divide 8 by 6 to get your final answer.

Hope this helps.

6 0

3 years ago

if Dakota earned $15.75 in interest in account A and $28.00 in interest in account B after 21 months. if the simple interest rat

NISA [10]

keeping in mind that 21 months is more than a year, since there are 12 months in a year, then 21 months is really 21/12 years.

$\bf ~~~~~~ \stackrel{\textit{account A}}{\textit{Simple Interest Earned}} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill &15.75\\ P=\textit{original amount deposited}\dotfill \\ r=rate\to 3\%\to \frac{3}{100}\dotfill &0.03\\ t=years\to \frac{21}{12}\dotfill &\frac{7}{4} \end{cases} \\\\\\ 15.75=P(0.03)\left( \frac{7}{4} \right)\implies \cfrac{15.75}{(0.03)\left( \frac{7}{4} \right)}=P\implies \boxed{300=P}$

$\bf ~~~~~~ \stackrel{\textit{account B}}{\textit{Simple Interest Earned}} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill &28\\ P=\textit{original amount deposited}\dotfill \\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ t=years\to \frac{21}{12}\dotfill &\frac{7}{4} \end{cases} \\\\\\ 28=P(0.049)\left( \frac{7}{4} \right)\implies \cfrac{28}{(0.049)\left( \frac{7}{4} \right)}=P\implies \boxed{326.53\approx P}$