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alexandr1967 [171]
3 years ago
14

2x-7=-3x9 what value of x would make this equation true

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
4 0

Answer: x = -10

Step-by-step explanation:

lianna [129]3 years ago
3 0

Answer:

17

Step-by-step explanation:

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35 into binary number<br>​
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35 in binary is 100011.

Step-by-step explanation:

To find decimal to binary equivalent, divide 35 successively by 2 until the quotient becomes 0.

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3 years ago
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Difference in elevation between mount Everest and Dead sea
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The difference is 27, 735 ft


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A pink crayon is made with 12 ML’s of red wax for every five ML of white wax
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kewl

Step-by-step explanation:

4 0
3 years ago
Find the number to which the sequence {(3n+1)/(2n-1)} converges and prove that your answer is correct using the epsilon-N defini
Nat2105 [25]
By inspection, it's clear that the sequence must converge to \dfrac32 because

\dfrac{3n+1}{2n-1}=\dfrac{3+\frac1n}{2-\frac1n}\approx\dfrac32

when n is arbitrarily large.

Now, for the limit as n\to\infty to be equal to \dfrac32 is to say that for any \varepsilon>0, there exists some N such that whenever n>N, it follows that

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|

From this inequality, we get

\left|\dfrac{3n+1}{2n-1}-\dfrac32\right|=\left|\dfrac{(6n+2)-(6n-3)}{2(2n-1)}\right|=\dfrac52\dfrac1{|2n-1|}
\implies|2n-1|>\dfrac5{2\varepsilon}
\implies2n-1\dfrac5{2\varepsilon}
\implies n\dfrac12+\dfrac5{4\varepsilon}

As we're considering n\to\infty, we can omit the first inequality.

We can then see that choosing N=\left\lceil\dfrac12+\dfrac5{4\varepsilon}\right\rceil will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that N\in\mathbb N.
6 0
3 years ago
The waterfall trail is 3/4 mile long at 1/6 of the distance from the shore head there is a workout in Miles how far is the looko
Komok [63]
1/6 of 3/4 mile = 1/6 * 3/4 = 1/8 = 0.125 mile

The correct result would be 1/8 or 0.125 mile.
4 0
3 years ago
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