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Arlecino [84]
3 years ago
8

A train leaves Roseville heading east at 6:00 am at 40 miles per hour. Another eastbound train leaves on a parallel track at 7:0

0 am at 50 miles per hour. What times will it be when the two trains are at the same distance away from Roseville?
Mathematics
1 answer:
Molodets [167]3 years ago
6 0

Answer:

At 11:00 am the both trains will be at same distance away from Roseville

Step-by-step explanation:

The first train was 40 miles away from Roseville at 7:00 am

After some time t the both trains will be at the same distance away from Roseville.

We will make equation for that situation

d- distance      v1= 40mph and v2= 50mph -  velocity

d =  v1*t + 40 = v2*t  => v2*t - v1*t = 40 => t (v2-v1) = 40 -> t = 40/ (v2-v1)

t = 40/(50-40) = 40/10= 4h      t = 4h

7:00 am * 4h = 11:00 am

Good luck!!!

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Answer:

350gallons /minute

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jarptica [38.1K]
You can rearrange f(x) as:

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Read 2 more answers
PLEASE HELP FAST! I'LL LIST U BRAINIEST IF U ANSWER RIGHT!
sattari [20]

Answer:

Part A) x = -3

Part B) x = 1, x = -7

Part C) x < -7

Part D) 2

Step-by-step explanation:

<h3>Part A)</h3>

2(x - 3) = 3x - 3

<em>open the parenthesis</em>

2 * x - 2 * 3 = 3x - 3

2x - 6 = 3x - 3

<em>subtract 2x from both sides</em>

2x - 2x - 6 = 3x - 2x - 3

-6 = x - 3

<em>add 3 to both sides</em>

-6 + 3 = x

-3 = x

<h3>Part B)</h3>

|2x + 6| = 8

<em>split this into two equations:</em>

<em>2x + 6 = 8</em>

<em>&</em>

<em>2x + 6 = -8</em>

2x + 6 = 8

2x = 8-6

2x = 2

x = 1

2x + 6 = -8

2x = -8 - 6

2x = -14

x = -7

<h3>Part C)</h3>

-5(x + 1) > 30

<em>open the parenthesis</em>

-5x - 5 > 30

<em>add 5 to both sides</em>

-5x > 35

<em>divide both sides by -5</em>

x > -7

<em>since you divided by a negative, flip the sign.</em>

x < -7

<h3>Part D)</h3>

f(x) = 4x - 3

<em>substitute x for 5</em>

5 = 4x - 3

5 + 3 = 4x

8 = 4x

2 = x

5 0
3 years ago
Some help figuring out the answer?? Also explain a little how you got there
ipn [44]

9514 1404 393

Answer:

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Step-by-step explanation:

Apparently, we are to assume that the horizontal lines are parallel to each other.

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  Sin = Opposite/Hypotenuse

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Then ...

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Substituting for BX and XA using the above relations, we get

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Solving for x gives ...

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_____

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klemol [59]

Answer:

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