Question

A train leaves Roseville heading east at 6:00 am at 40 miles per hour. Another eastbound train leaves on a parallel track at 7:00 am at 50 miles per hour. What times will it be when the two trains are at the same distance away from Roseville?

Answer 1

Answer:

At 11:00 am the both trains will be at same distance away from Roseville

Step-by-step explanation:

The first train was 40 miles away from Roseville at 7:00 am

After some time t the both trains will be at the same distance away from Roseville.

We will make equation for that situation

d- distance      v1= 40mph and v2= 50mph -  velocity

d =  v1*t + 40 = v2*t  => v2*t - v1*t = 40 => t (v2-v1) = 40 -> t = 40/ (v2-v1)

t = 40/(50-40) = 40/10= 4h      t = 4h

7:00 am * 4h = 11:00 am

Good luck!!!