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3 years ago

If the diagonal of a square is 11.3 meters, approximidley what is the perimeter of the square?

Mathematics

1 answer:

Andrei [34K]3 years ago

8 0

Answer:

About 9.6 meters

Step-by-step explanation:

Refer to attachment

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Please help me thank you. :)

Dmitry_Shevchenko [17]

1. x=6,y=8
2. x=5,y=7

7 0

3 years ago

If y varies directly as x, and y = 10 when x = 9, find y when x = 1/9

Vinvika [58]

Answer:

10/81

Step-by-step explanation:

let,

y=kx

y=10 when x=9

so,

10=k×9

or, k=10/9

when x=1/9

y=kx

or, y=(10/9)×(1/9)

or, y=10/81

5 0

2 years ago

2x-3y=32<br> 1/2(2X+3y)=-8

Alex787 [66]

Answer:

x=4 :y=-8

Just ut Equation in Scientific Calculator or Symbolab App or WEb search Equation solver

8 0

2 years ago

3<br>Find the value of a <br>in the equation,(3+4√3)(2-a√3)=-18+2√3

ankoles [38]

Given:

The equation is:

$\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}$

To find:

The value of a.

Solution:

We have,

$\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}$

On simplification, we get

$(3)(2)+(4\sqrt{3})(2)+(3)(-a\sqrt{3})+(4\sqrt{3})(-a\sqrt{3})=-18+2\sqrt{3}$

$6+8\sqrt{3}-3a\sqrt{3}-4a(3)=-18+2\sqrt{3}$

$6+8\sqrt{3}-3a\sqrt{3}-12a=-18+2\sqrt{3}$

$(6-12a)+(8-3a)\sqrt{3}=-18+2\sqrt{3}$

On comparing both sides, we get

$6-12a=-18$

$-12a=-18-6$

$a=\dfrac{-24}{-12}$

$a=2$

And,

$8-3a=2$

$-3a=2-8$

$a=\dfrac{-6}{-3}$

$a=2$

Therefore, the value of a is 2.

3 0

2 years ago

Find the solutions x2 = 27

Aneli [31]

Answer:

27 divided by 3 is 9

27 divided by 2 is 13.5

x = 13.5

Re written...

(13.5)2 = 27

make sense?

7 0

2 years ago