Let x be for unknown number. Let x be first number .
X+1 To be second number .x+2be third number. X+(x+1)+(x+2)=312.
Simplify to get 3x+3=312 . Subtract 3 from both sides 3x-3=312-3. Once you subtract get 3x=109.then divide 3 both sides . 3x/3=309/3. To get x= 103.
Now once you have that First number 103. Second number 103+1=104 . And third number 103+2=105. To check add them 103+104+105=312
B pretty sure that it’s that
Answer:
Where are the questions....?
Answer: none of those, 276...?
Step-by-step explanation:
You need to know the least common denominator (LCD) of 12 and 23 if you want to add or subtract two fractions with 12 and 23 as denominators.
The least common denominator, also called lowest common denominator (LCD), of 12 and 23 is 276.
Here is a math problem example where you need to know the LCD of 12 and 23 to solve:
3/12 + 2/23 = ?
Step 1) Take the LCD and divide each denominator by it as follows:
276/12 = 23
276/23 = 12
Step 2) Multiply each nominator with the respective answers from Step 1:
3 x 23 = 69
2 x 12 = 24
Step 3) Put it all together to solve the problem:
69/276 + 24/276 = 93/276
= 3/12 + 2/23 = 93/276
It's that easy! Once again, the lowest common denominator (LCD) of 12 and 23 is as follows:
276
The exponential function
f(x) = a^x
can pass through all points as long as x is any real number
As an example, we can choose values of x.
x = -4, x = 0, x=100
The value of the function in terms of a would be
f(-4) = a^-4
f(0) = a^0 = 1
f(100) = a^100
