Since the slope stays the same as it's parallel, we have y=(3/4)x+b. Plugging (2,-1) in, we get -1=3*2/4+b=6/4+b=1.5+b. Subtracting 1.5 from both sides, we get -2.5=b and our equation being y=(3/4)x-2.5 (since in y=mx+b, y and x remain as variables)
Answer:
Step-by-step explanation:
The rocket will hit the ground when y = 0. If you use the quadratic equation:
x = (-248±√(2482-4(-16)(116))/(2(-16))
k = 18
the common difference d of an arithmetic sequence is
d = a₂ - a₁ = a₃ - a₂ = ....
a₂ - a₁ = 2k - 1 - k - 9 = k - 10 and
a₃ - a₂ = 2k + 7 - (2k - 1) = 2k + 7 - 2k + 1 = 8, hence
k - 10 = 8 ⇒ k = 8 + 10 = 18
the 3 consecutive terms are
27, 35, 43
-7 x -3 x 7k
-7 x -3 = -31k
