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3 years ago

6

I need help and I have to do what it says

1 answer:

Andreas93 [3]3 years ago

3 0

X^2 + 6x = -2 is a quadratic equation that can be solved by completing the square.

x^2 + 6x + (6/2)^2 - (6/2)^2 = -2

Rewriting this, (x+3)^2 = -2 + (6/2)^2 = -2 + 9 = 7

tAKING THE sqrt f both sides, we get x+3 = plus or minus 5.

Finally, x = -3 plus or minus 5, which boils down to x=2 and x= -8.

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28= -2u<br> u= ?<br> Basically, U equals what?

vredina [299]

Answer: U=-14
Explanation:

4 0

2 years ago

Working alone and at a constant rate, Machine A takes 3 hours to create a widget. Machine B, working alone and at a constant rat

PilotLPTM [1.2K]

Answer:

Time required by Machine B to create a widget = 4 hours

Step-by-step explanation:

Time taken by Machine A ( $T_{A}$ ) = 3 hours

Time taken by Machine B ( $T_{B}$ )= x hours

Time taken by both machines by working together = 12 hours

The time required to both machines by working together to finish a task is given by the formula = $\frac{T_{A} {T_{B} } }{T_{A} + T_{B} }$

Put the values in above formula we get

⇒ T = $\frac{3 x}{3 + x}$

⇒ 12 = $\frac{3 x}{3 + x}$

⇒ 36 + 12 x = 3 x

⇒ x = - 4 hours

This is the time required by Machine B to create a widget.

8 0

3 years ago

An uber in Los Angeles charges $3.50 per mile and $2 for every person. If taxi cab ride for three people costs $20, how far did

Vsevolod [243]

Answer:

4 miles

Step-by-step explanation:

5 0

3 years ago

Find the percent of each number 0.9 of 1000

trasher [3.6K]

We can use the is/of = p/100 method here. Our given values are 90% and 1000. Think: "What number is 90% of 1000?" Let's plug in our values.

x/1000 = 90/100

Solve for x.

x = (1000)(0.9)

x = 900

So, 900 is 90% of 1000.

8 0

3 years ago

If log a = x and log b = y, then log (ab2) equals

mylen [45]

Answer:

The answer for log(ab²) is x + 2y.

Step-by-step explanation:

You have to apply Logarithm Law,

$log(a) + log(b) \: ⇒ \: log(a \times b)$

$log( {a}^{n} ) \: ⇒ \: n log(a)$

In this question, you have to seperate it out :

$log(a {b}^{2} ) = log(a) + log( {b}^{2} )$

$log( {b}^{2} ) = 2 log(b)$

$let \: log(a) = x$

$let log(b) = y$

$log(a {b}^{2} ) = log(a) + 2 log(b)$

$log(a {b}^{2} ) = x + 2y$

3 0

3 years ago