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Lena [83]
3 years ago
6

Sum of money is placed at simple interest for 3 years at 10% per annum and then the amount is invested for 2 years at the same r

ate at compound interest . If the total amount of 5 years became Rs. 471900, what was the sum?
​
Mathematics
1 answer:
JulsSmile [24]3 years ago
3 0

Answer:

sum was 300000

Step-by-step explanation:

let sum of money is placed  is x rs

Term T = 3 years, rate R = 10%

Then simple interest for for 3 years is

SI= \frac{PTR}{100}\\ SI=\frac{x\times 3\times 10}{100} \\SI = 0.3x

Sum of x will become x+0.3x = 1.3x after 3 years. now this 1.3x is kept for compound interest for two years. ie

A =P[1+R]^t\\471900=1.3x[1+\frac{10}{100} ]^2\\x=\frac{471900}{1.573} \\x=300000

Sum was 300000

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<h3>Domain and Range</h3>

The domain of a function is the set of input values for which the function is real and defined. In the other words, when you define the domain, you are indicating for which values x the function is real and defined.

While the domain is related to the values ​​of x, the range is related to the possible values ​​of y that the function can have.

Here, you need to replace the given domain values in the equation: f(x)=x-4. The question gives that the domain is represented by: -2 ,0 ,2 .

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For x=-2, you have:

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3 years ago
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Step-by-step explanation:

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